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3 years ago

If p is true and q is false, the p ---> q is (always, never, sometimes) true.

Mathematics

2 answers:

garri49 [273]3 years ago

5 0

I believe the answer your look for is ....[ALWAYS]

natulia [17]3 years ago

5 0

Answer:

The correct answers are filled up below:

Step-by-step explanation:

If p is true and q is false, the p ---> q is (always) true.

When p is false and q is true, then p or q is (always) true.

If p is true and ~ q is false, then p ---> ~ q is (always, ) false.

If p is true and q is true, then ~ p ---> ~ q is (always) true.

If p ---> q is true and q is true, then p is (always, ) true

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kherson [118]

$\sf{\qquad\qquad\huge\underline{{\sf Answer}}}$

Here we go ~

take value of pi = 3

r = radius = 5 cm

h = height = 9 cm

Let's calculate volume of Cylinder ~

$\qquad \sf \dashrightarrow \:v = \pi {r}^{2} h$

$\qquad \sf \dashrightarrow \:v = 3 \times {5}^{2} \times 9$

$\qquad \sf \dashrightarrow \:v = 3\times25 \times 9$

$\qquad \sf \dashrightarrow \:v = 75 \times 9$

$\qquad \sf \dashrightarrow \:v =67 5 \: \: cm {}^{3}$

That's all, ask me if you have any queries ~

7 0

2 years ago

Geometry.

navik [9.2K]

The equation of a circle with center (h, k) and radius r is

$(x - h)^{2} + (y - k)^{2} = r^{2}$

In this case, the center of the circle is (-3, 2), and the radius is 3.
You have h = -3, k = 2, r = 3

$(x- (-3))^{2} + (y - 2)^{2} = 3^{2}$

Simplifying, you get

$(x + 3)^{2} + (y - 2)^{2} = 9$

7 0

4 years ago

What is 7.1 as an improper fraction

Advocard [28]

The answer is 1.7 there you go.

7 0

4 years ago

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Iteru [2.4K]

Answer:

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