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3 years ago

HELP AHHHHHHHHHHHHHHHHHHHHHHHHHHHHHH

Mathematics

1 answer:

diamong [38]3 years ago

5 0

Answer:

3x+12y+4 -- is the simplified version, variables would be x and y

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Cheryl moves houses. Her old house is 3 kilometers from her new house. How many meters is it from the old house to the new house

d1i1m1o1n [39]

Answer:

3000 here hope this helps you out

3 0

3 years ago

For what value of x does the function have an output of -7, given that g(x) = -3x + 8

madam [21]

Answer:

X=5

Step-by-step explanation:

-3x+8=-7

-3x=-15

X=5

4 0

3 years ago

The distance d traveled at a constant speed r is directly proportional to the time t spent traveling. a car moving at a constant

svet-max [94.6K]

150/2.5=x/6 is the proportion

3 0

3 years ago

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Find the average value of the function on the given interval.<br> f(x)=ex/7; [0,7]

Anastaziya [24]

Answer:

$f_{avg}=e-1$

Step-by-step explanation:

We are given that a function

$f(x)=e^{\frac{x}{7}}$

We have to find the average value of function on the given interval [0,7]

Average value of function on interval [a,b] is given by

$\frac{1}{b-a}\int_{a}^{b}f(x)dx$

Using the formula

$f_{avg}=\frac{1}{7-0}\int_{0}^{7}e^{\frac{x}{7}} dx$

$f_{avg}=\frac{1}{7}[e^{\frac{x}{7}}\times 7)]^{7}_{0}$

By using the formula

$\int e^{ax}=\frac{e^{ax}}{a}$

$f_{avg}=(e-e^0)=e-1$

Because $e^0=1$

$f_{avg}=e-1$

Hence, the average value of function on interval [0,7]

$f_{avg}=e-1$

8 0

3 years ago

HELP PLEASE

Gnesinka [82]

Answer: $x^2=8y$

Step-by-step explanation:

Let the given parabolic mirror opens upwards and vertex=(0,0)

Focus point of the parabolic mirror is located 2 inches from the vertex of the mirror. ∴ p=2

Since, the parabola opens upward, then the equation of the parabola is of the form $x^2=4py$

Substitute the value of p=2 in this, we get the equation of the parabolic mirror

$x^2=4(2)y\\\Rightarrow\ x^2=8y$

Hence, the equation of the parabola that models the cross section of the mirror is $x^2=8y$

7 0

3 years ago

Read 2 more answers