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N76 [4]
3 years ago
6

HELP AHHHHHHHHHHHHHHHHHHHHHHHHHHHHHH

Mathematics
1 answer:
diamong [38]3 years ago
5 0

Answer:

3x+12y+4 -- is the simplified version, variables would be x and y

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1/7 cups per serving

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Which integer is 30 closest to
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7,4,15,6

Step-by-step explanation:

7,4,15,6

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Answer: T (The first option).


Step-by-step explanation:

1. By definition, coplanar points are three or more points that are in the same plane.

2. Based on this information, as you can see in the figure attached, the points A, C, D, E, S and U are coplanars because they are in the same plane, which is: ACDE.

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3 0
2 years ago
Write the equation for the hyperbola with foci (–12, 6), (6, 6) and vertices (–10, 6), (4, 6).
fomenos

Answer:

\frac{(x--3)^2}{49} -\frac{(y-6)^2}{32}=1

Step-by-step explanation:

The standard equation of a horizontal hyperbola with center (h,k) is

\frac{(x-h)^2}{a^2}-\frac{(y-k)^2}{b^2}=1

The given hyperbola has vertices at (–10, 6) and (4, 6).

The length of its major axis is 2a=|4--10|.

\implies 2a=|14|

\implies 2a=14

\implies a=7

The center is the midpoint of the vertices (–10, 6) and (4, 6).

The center is (\frac{-10+4}{2},\frac{6+6}{2}=(-3,6)

We need to use the relation a^2+b^2=c^2 to find b^2.

The c-value is the distance from the center (-3,6) to one of the foci (6,6)

c=|6--3|=9

\implies 7^2+b^2=9^2

\implies b^2=9^2-7^2

\implies b^2=81-49

\implies b^2=32

We substitute these values into the standard equation of the hyperbola to obtain:

\frac{(x--3)^2}{7^2} - \frac{(y-6)^2}{32}=1

\frac{(x+3)^2}{49} -\frac{(y-6)^2}{32}=1

7 0
3 years ago
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