3 years ago

Express as decimal numerals one and three hundred twenty four thousandths

Mathematics

2 answers:

nadya68 [22]3 years ago

5 0

The answer would be 1.324

snow_tiger [21]3 years ago

4 0

As a decimal 1.324 is the answer

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What are the points of discontinuity y=(x-5)/x^2-6x+5?

ollegr [7]

$y = \frac{x - 5}{x^{2} - 6x + 5}$
$y = \frac{x - 5}{(x - 1)(x - 5)}$
$y = \frac{1}{x - 1}$

x - 1 = 0
+ 1 + 1
x = 1

3 0

3 years ago

Bennett tried to solve exercise 1 a few different ways. Which of his methods are correct? Of the other methods, which makes the

nasty-shy [4]

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4 0

3 years ago

Simplify 4x + 8y - 3x + 2y

mezya [45]

Answer: 4x-3x, and 8y+2y. x+10y is the equation in simplest form.

Step-by-step explanation:

Step 1. You need to combine like terms:

4x-3x, and 8y+2y. x+10y would make the equation( 4x + 8y - 3x + 2y) in simplified form.

Hope I could help! :)

7 0

3 years ago

Read 2 more answers

Select the correct location in the expression.

kogti [31]

Answer:

Correct term:60

Step-by-step explanation:

We are given that

$\frac{4x^4-6x^3+6x+3}{x-3}$

The quotient of this expression is given by

$4x^3+6x^2+18x+78+\frac{183}{x-3}$

We have to find the term in this expression which contains an error.

$\frac{4x^4-6x^3+6x+3}{x-3}$

The quotient of this expression is given by

$=4x^3+6x^2+18x+60$

$Dividend=Divisor\times quotient+ remainder$

Using the formula

$4x^4-6x^3+6x+3=(x-3)(4x^3+6x^2+18x+60)+\frac{183}{x-3}$

We can see that in the given expression there is 60 in place of 78.

The error in the expression of quotient is 78.

Correct term is 60.

4 0

3 years ago

10 points pls answer!!!!

lutik1710 [3]

Answer:

add them togethr then subract the diffrece to get x

Step-by-step explanation:

7 0

2 years ago