Let

be the n'th term of the sequence.
so

is the first term,

the second term and so on...
In a geometric sequence with

, and common ratio r, the terms are as follows:




.
.
that is, each term is its previous term times the common ratio r.
In our example

and


so


Answer: r=0.75
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Answer:
m∠HMO=102°
Step-by-step explanation:
we know that
In a Rhombus the diagonals bisect the angles and opposite angles are equal
In this problem
Angles HMO and HTO are opposite angles
m∠HMO=m∠HTO
m∠HTM=(1/2)m∠HMO ----> because the diagonals bisect the angles and opposite angles are congruent
substitute the values

solve for x

<em>Find the measure of angle HMO</em>
m∠HMO=(12x-6)°
substitute the value of x
m∠HMO=(12(9)-6)=102°
see the attached figure to better understand the problem
Answer:
-6
Step-by-step explanation:
Trust me fam