The LCM<span> of 42 and 54 is 378.</span>
The function is:
f ( x ) = x² - x - 72
This is a quatdratic function. So we can find the zeroes of the function with the formula:
x 1/2 = ( - b +/- √(b² - 4 ac) ) / ( 2a )
And we have: a = 1, b = - 1 and c = - 72
x 1/2 = ( 1 +/- √((-1)² - 4 · 1· ( - 72 )) ) / 2
x 1/2 = ( 1 +/- √( 1 + 288 ) ) / 2
x 1/2 = ( 1 +/- √289 ) / 2
x 1/2 = ( 1 +/- 17 ) / 2
x 1 = ( 1 - 17 ) 2 = - 16 / 2 = - 8
x 2 = ( 1 + 17 ) / 2 = 18 / 2 = 9
Answer: The zeroes are - 8 and 9.
The mean will be 5 points higher...so...c would be the answer!
Answer:
b/h
Step-by-step explanation:
remember SOH CAH TOA. Sin = opposite/hypotenuse, cos = adjacent/hypotenuse, tan = opposite/adjacent. So in this case use CAH for cos L. Adjacent to L is b, and the hypotenuse is h. Therefore the answer is b/h.
Answer:
37.59 nautical miles
Explanation:
Distance = Speed x Time
The speed of the first ship = 12 knots
Thus, the distance covered after 1.5 hours
The speed of the second ship = 22 knots
Thus, the distance covered after 1.5 hours
The diagram representing the ship's path is drawn and attached below:
The angle at port = 90 degrees.
The triangle is a right triangle.
Using Pythagorean Theorem:
![\begin{gathered} c^2=a^2+b^2 \\ c^2=18^2+33^2 \\ c^2=324+1089 \\ c^2=1413 \\ c=\sqrt[]{1413} \\ c=37.59\text{ miles} \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20c%5E2%3Da%5E2%2Bb%5E2%20%5C%5C%20c%5E2%3D18%5E2%2B33%5E2%20%5C%5C%20c%5E2%3D324%2B1089%20%5C%5C%20c%5E2%3D1413%20%5C%5C%20c%3D%5Csqrt%5B%5D%7B1413%7D%20%5C%5C%20c%3D37.59%5Ctext%7B%20miles%7D%20%5Cend%7Bgathered%7D)
The two ships are 37.59 nautical miles apart after 1.5 hours.
