Simplify the expression. 2.3h(6-k)
1 answer:
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<h3>I'm solving it using substitution method:-</h3><h3>7x+2y=3 {given}</h3><h3>=>7x=3-2y</h3><h3>=>x=(3-2y)/7-------(1)</h3><h3>x-3y=30 {given}</h3><h3>=>x=30+3y</h3><h3>=>(3-2y)/7=30+3y {putting the value of x from eqn 1}</h3><h3>=>3-2y=210+21y</h3><h3>=>3-210=21y+2y</h3><h3>=>-207=23y</h3><h3>=>y= -207/23= -9</h3><h3>putting the value of y on eqn(1):-</h3><h3>x=(3-2y)/7</h3><h3>x=>(3-2(-9))/7=(3+18)/7=21/7=3</h3><h2>Hence, x=3, y= -9</h2>✌️✌️❤️❤️
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Answer:
-1
Step-by-step explanation:
For a line joining two points (x1, y1) and (x2, y2), it's slope is given as:
Here, the two points are (-1, 6) and (2, 3) in place of (x1, y1) and (x2, y2).
Solving for slope:
Hence, the slope of the line joining the given points is <u>-1.</u>