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fiasKO [112]
2 years ago
15

While surveying Overlook Cave, Mike measures the angle of elevation from his line of sight to the top of a rock formation as 22°

. The rock formation is 10 feet away and he is measuring from a point 3 feet above the floor of the cave. To the nearest tenth of a foot, how high is the rock formation?
Mathematics
1 answer:
Kaylis [27]2 years ago
7 0

Answer:

The rock formation is approximately 7 feet tall.

Step-by-step explanation:

<em>We can visualize this situation as a triangle and know that the bottom side is </em><em>10</em><em> and the angle of elevation (the angle created by Mike and the ground, looking to the top of a rock). With this information, we can use tangent to solve.</em>

<em>x = the height of the rock formation</em>

tan(22°) = x/10

10 tan(22°) = x

x = ~4.04 feet

<em>We also have to add the </em><em>3 feet</em><em> to it because it is being measured 3 feet above the floor.</em>

x + 3 = 7.04 feet

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