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3 years ago

HELP I WILL GIVE LOTS OF BRIANLY POINTS!!!!!!! PLZ EXPLAINM A BIT TOO FOR BRAINLY REWARD!!!

Mathematics

1 answer:

worty [1.4K]3 years ago

6 0

Answer: 25

Step-by-step explanation:

20 - 25 = -5

20 - 20 = 0

0 - 5 = -5

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H(y)=4|y+2|−3, evaluate h(−8).

nikdorinn [45]

Answer:

h(-8)=21

Step-by-step explanation:

-8+2=-6

abs(-6)=6

4*6=24

24-3

7 0

3 years ago

Please help me on this I don't know how to do this help me to find out what property it is thank you . .

Agata [3.3K]

Distributive
it has parenthese which you have to multiply with
x= infinite solution btw

8 0

3 years ago

5p−3p+9+p+3? pls im failingg

Triss [41]

Answer:

3p + 12

Step-by-step explanation:

5p -3p + 9 + p + 3

Move around the parts of the equation

5p -3p + p + 9 + 3

Add positive 9 to positive 3

5p -3p + p + 12

Add positive p to negative 3p

5p -2p + 12

Combine positive 5p and negative 2p together

3p + 12

I Hope That This Helps! :)

7 0

3 years ago

Raquel attended a volleyball game that began at 9:30am and ended at 11:45 am she began her lunch at 12:00 pm and ended lunch at

Reil [10]

Answer:

Raquel spend 2 hr 15 Minutes at the volley ball game and 1 hour at the lunch

Step-by-step explanation:

Time Spent at the Volley ball match

The difference of 11:45 and 9 :30 is 2:15 which indicate she spend 2 hour and 15 minutes at the lunch.

sameway , from 12 pm to 1 pm , it encounter a difference of 1 Hour.

hence , she spent 1 hr at lunch.

8 0

3 years ago

g A plane flying horizontally at an altitude of 2 miles and a speed of 550 mi/h passes directly over a radar station. Find the r

guapka [62]

Answer:

The rate at which the distance from the plane to the station is increasing is when it is 5 miles away from the station is 504 mi/h

Step-by-step explanation:

An illustrative diagram for the scenario is shown in the attachment below.

In the diagram, y represent the altitude, z is the horizontal distance from the plane to the station and x is the distance from the plane to the station.

From the Pythagorean theorem, we can write that

x² = y² + z²

Differentiate this with respect to time t

That is,

$\frac{d}{dt}(x^{2}) = \frac{d}{dt}(y^{2}) + \frac{d}{dt}(z^{2})$

= $2x(\frac{dx}{dt}) = 2y(\frac{dy}{dt}) + 2z(\frac{dz}{dt})$

$x(\frac{dx}{dt}) = y(\frac{dy}{dt}) + z(\frac{dz}{dt})$

The rate at which the distance from the plane to the station is increasing is $\frac{dx}{dt}$

$\frac{dy}{dt}$ is the rate at which the altitude is increasing, since the altitude is 2, that is constant, $\frac{dy}{dt} = 0$ .

$\frac{dz}{dt}$ is the rate at which the horizontal distance is increasing which is the speed, that is, $\frac{dz}{dt} = 550 mi/h$

$y = 2$ and $x = 5$

Now, we will determine z when x = 5.

From x² = y² + z²

5² = 2² + z²

25 = 4 + z²

z² = 25-4

z² = 21

z =√21

Putting all the values into the equation

$x(\frac{dx}{dt}) = y(\frac{dy}{dt}) + z(\frac{dz}{dt})$

$5(\frac{dx}{dt}) = 2(0) + \sqrt{21} (550)$

$5(\frac{dx}{dt}) = \sqrt{21} (550)$

$\frac{dx}{dt} = \frac{\sqrt{21} (550)}{5}$

$\frac{dx}{dt} = 504 mi/h$

Hence, the rate at which the distance from the plane to the station is increasing is when it is 5 miles away from the station is 504 mi/h.

5 0

3 years ago