Answer:
-2y^2 -x^2 -5
Step-by-step explanation:
Just simplify everything. I recomend putting them in seperate groups. By exponent. Don't forget the signs, they are very important.
Answer:
The number in the middle is 60.
Step-by-step explanation:
The 2nd number = A
The 3rd number = B
The 4th number = C
Given:
(1) 130 + A + B = 300
(2) A + B + C = 200
(3) B + C + 10 = 100
Now, the work:
(2) can be modified to become A + B = 200 - C
Now, we can insert that into (1) and get the following;
130 + (200 - C) = 300
Open parentheses, simplify, you get C = 330 - 300.
C = 30
Using (3), we use above answer to get B + 30 + 10 = 100
Calculate, and get B = 100 - (30 + 10)
Simplify,
B = 60
There is your answer!
Cheers
Answer:
m<RPS = 53 degrees
Step-by-step explanation:
Find the diagram attached
From the diagram shown;
m<QPR + m<RPS = 90
Given that;
m<QPR = x
m<RPS = x+16
Substitute into the formula;
m<QPR + m<RPS = 90
x+x+16 = 90
2x+16 = 90
2x = 90-16
2x = 74
x = 74/2
x = 37degrees
Get m<RPS;
Since m<RPS = x+16
m<RPS = 37 + 16
m<RPS = 53 degrees
We know that the angles of a triangle sum to 180°. For ΔABC, this means we have:
(4x-10)+(5x+10)+(7x+20)=180
Combining like terms,
16x+20=180
Subtracting 20 from both sides:
16x=160
Dividing both sides by 16:
x=10
This means ∠A=4*10-10=40-10=30°; ∠B=5*10+10=50+10=60°; and ∠C=7*10+20=70+20=90.
For ΔA'B'C', we have
(2x+10)+(8x-20)+(10x-10)=180
Combining like terms,
20x-20=180
Adding 20 to both sides:
20x=200
Dividing both sides by 20:
x=10
This gives us ∠A'=2*10+10=20+10=30°; ∠B'=8*10-20=80-20=60°; and ∠C'=10*10-10=100-10=90°.
Since the angle are all congruent, ΔABC~ΔA'B'C' by AAA.
