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3 years ago

Which ordered pair is a solution of the equation? y -4 = 7(x – 6)

Mathematics

1 answer:

lions [1.4K]3 years ago

6 0

Answer:

more specific

Step-by-step explanation:

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Someone please help me get the answers to these

Varvara68 [4.7K]

2A) first find the measure of the angle above the right angle (180-122=58) so it equals 58°, while the right angle is obviously 90°. the whole triangle should be 180° so 90+58= 148. now we subtract this from 180 to get the measure for x. 180-148=32.

Therefore, x=32°

3 0

3 years ago

Please help -3/4(8n + 12) = 3(n-3)

Dennis_Churaev [7]

Step-by-step explanation:

$- \frac{3}{4} (8n + 12) = 3(n - 3)$

$- 3(8n + 12) = 12(n - 3)$

$\cancel{- 3}(8n + 12) = \cancel{12}(n - 3)$

$- (8n + 12) = 4(n - 3)$

$- 8n - 12 = 4n - 12$

$- 8n - 4n = - 12 + 12$

$- 12n = 0$

$n = 0$

8 0

2 years ago

compute the projection of → a onto → b and the vector component of → a orthogonal to → b . give exact answers.

Nina [5.8K]

$\text { Saclar projection } \frac{1}{\sqrt{3}} \text { and Vector projection } \frac{1}{3}(\hat{i}+\hat{j}+\hat{k})$

We have been given two vectors $\vec{a}$ and $\vec{b}$ , we are to find out the scalar and vector projection of $\vec{b}$ onto $\vec{a}$

we have $\vec{a}=\hat{i}+\hat{j}+\hat{k}$ and $\vec{b}=\hat{i}-\hat{j}+\hat{k}$

The scalar projection of $\vec{b}$ onto $\vec{a}$ means the magnitude of the resolved component of $\vec{b}$ the direction of $\vec{a}$ and is given by

The scalar projection of $\vec{b}$ onto

$\vec{a}=\frac{\vec{b} \cdot \vec{a}}{|\vec{a}|}$

$\begin{aligned}&=\frac{(\hat{i}+\hat{j}+\hat{k}) \cdot(\hat{i}-\hat{j}+\hat{k})}{\sqrt{1^2+1^1+1^2}} \\&=\frac{1^2-1^2+1^2}{\sqrt{3}}=\frac{1}{\sqrt{3}}\end{aligned}$

The Vector projection of $\vec{b}$ onto $\vec{a}$ means the resolved component of $\vec{b}$ in the direction of $\vec{a}$ and is given by

The vector projection of $\vec{b}$ onto

$\vec{a}=\frac{\vec{b} \cdot \vec{a}}{|\vec{a}|^2} \cdot(\hat{i}+\hat{j}+\hat{k})$

$\begin{aligned}&=\frac{(\hat{i}+\hat{j}+\hat{k}) \cdot(\hat{i}-\hat{j}+\hat{k})}{\left(\sqrt{1^2+1^1+1^2}\right)^2} \cdot(\hat{i}+\hat{j}+\hat{k}) \\&=\frac{1^2-1^2+1^2}{3} \cdot(\hat{i}+\hat{j}+\hat{k})=\frac{1}{3}(\hat{i}+\hat{j}+\hat{k})\end{aligned}$

To learn more about scalar and vector projection visit:brainly.com/question/21925479

#SPJ4

3 0

1 year ago

Gravity Hospital purchased a new item of equipment on January 1,20X1. The equipment has an estimated useful life of ten years an

qaws [65]

Answer:

$25000

Step-by-step explanation:

If the salvage value is 20% of the cost, then 80% of the cost will be depreciated over 10 years. Over the 5 years from Jan 1 20X1 to Dec 31 20X5, the $10,000 accumulated depreciation represents 5/10 of that 80%, or 40% of the initial cost.

$10,000 = 0.40 × cost

$10,000/0.40 = cost = $25,000

The acquisition cost of the equipment was $25,000.

8 0

3 years ago

Find all roots: x^3 + 7x^2 + 12x = 0 Show all work and check your answer.

Aliun [14]

The three roots of x^3 + 7x^2 + 12x = 0 is 0,-3 and -4

Solution:

We have been given a cubic polynomial.

$x^{3}+7 x^{2}+12 x=0$