Answer:
Step-by-step explanation:
7259.75 - 7100 = 159.75
he earned 159.75 in interest
159.75/ 7100= .0225
and if you convert that to percentages then its 2.25%
Answer:
3185
Step-by-step explanation:
Answer:
x = 11
Step-by-step explanation:
ΔLKM is an equilateral because a triangle with all 3 sides that are congruent is an equilateral triangle.
Angles in an equilateral triangle are all 60°.
Thus, ∠L = 60°.
=> 3x + 27 = 60
=> 3x = 33
=> x = 11
Answer: a. 1.981 < μ < 2.18
b. Yes.
Step-by-step explanation:
A. For this sample, we will use t-distribution because we're estimating the standard deviation, i.e., we are calculating the standard deviation, and the sample is small, n = 12.
First, we calculate mean of the sample:
![\overline{x}=\frac{\Sigma x}{n}](https://tex.z-dn.net/?f=%5Coverline%7Bx%7D%3D%5Cfrac%7B%5CSigma%20x%7D%7Bn%7D)
![\overline{x}=\frac{2.31=2.09+...+1.97+2.02}{12}](https://tex.z-dn.net/?f=%5Coverline%7Bx%7D%3D%5Cfrac%7B2.31%3D2.09%2B...%2B1.97%2B2.02%7D%7B12%7D)
2.08
Now, we estimate standard deviation:
![s=\sqrt{\frac{\Sigma (x-\overline{x})^{2}}{n-1} }](https://tex.z-dn.net/?f=s%3D%5Csqrt%7B%5Cfrac%7B%5CSigma%20%28x-%5Coverline%7Bx%7D%29%5E%7B2%7D%7D%7Bn-1%7D%20%7D)
![s=\sqrt{\frac{(2.31-2.08)^{2}+...+(2.02-2.08)^{2}}{11} }](https://tex.z-dn.net/?f=s%3D%5Csqrt%7B%5Cfrac%7B%282.31-2.08%29%5E%7B2%7D%2B...%2B%282.02-2.08%29%5E%7B2%7D%7D%7B11%7D%20%7D)
s = 0.1564
For t-score, we need to determine degree of freedom and
:
df = 12 - 1
df = 11
= 1 - 0.95
α = 0.05
0.025
Then, t-score is
= 2.201
The interval will be
± ![t.\frac{s}{\sqrt{n} }](https://tex.z-dn.net/?f=t.%5Cfrac%7Bs%7D%7B%5Csqrt%7Bn%7D%20%7D)
2.08 ± ![2.201\frac{0.1564}{\sqrt{12} }](https://tex.z-dn.net/?f=2.201%5Cfrac%7B0.1564%7D%7B%5Csqrt%7B12%7D%20%7D)
2.08 ± 0.099
The 95% two-sided CI on the mean is 1.981 < μ < 2.18.
B. We are 95% confident that the true population mean for this clinic is between 1.981 and 2.18. Since the mean number performed by all clinics has been 1.95, and this mean is less than the interval, there is evidence that this particular clinic performs more scans than the overall system average.
The answer would be -21.6