Br- + 2MnO4- + 2H+ → BrO3- + 2MnO2 + H2O
<h3>Further explanation</h3>
Given
MnO4- + Br- = MnO2 + BrO3-
Required
The half-reaction
Solution
In acidic conditions :
1. Add the coefficient
2. Equalization O atoms (add H₂O) on the O-deficient side.
3. Equalization H atoms (add H⁺ ) on the H -deficient side. .
4. Equalization of charge (add electrons (e) )
5. Equalizing the number of electrons and then adding the two half -reactions together
Oxidation : Br- → BrO3-
Reduction : MnO4- → MnO2
Br- + 3H2O → BrO3-
MnO4- → MnO2 + 2H2O
Br- + 3H2O → BrO3- + 6H+
MnO4- + 4H+ → MnO2 + 2H2O
Br- + 3H2O → BrO3- + 6H+ + 6e- x1
MnO4- + 4H+ + 3e- → MnO2 + 2H2O x2
- Equalizing the number of electrons and then adding the two half -reactions together
Br- + 3H2O → BrO3- + 6H+ + 6e-
2MnO4- + 8H+ + 6e- → 2MnO2 + 4H2O
Br- + 2MnO4- + 3H2O + 8H+ + 6e- → BrO3- + 2MnO2 + 6H+ + 4H2O + 6e-
Br- + 2MnO4- + 2H+ → BrO3- + 2MnO2 + H2O
Considering that copper occupies Group 11, the ionic compound with a transition metal in it is c. CuSO₄.
<h3>What is a transition metal?</h3>
A transition metal is any of the set of metallic elements occupying a central block (Groups 3–12) in the periodic table. The differential electron occupies a d subshell.
Which of the following ionic compounds has a transition metal in it?
- a. KOH. No, K occupies Group 1.
- b. Cs₂S. No, Cs occupies Group 1.
- c. CuSO₄. Yes, Cu occupies Group 11.
- d. MgCl₂. No, Mg occupies Group 2.
The ionic compound with a transition metal in it is c. CuSO₄.
Learn more about transition metals here: brainly.com/question/2426896
The writers of the Articles of Confederation wanted to preserve the states' sovereignty.
<u>Answer:</u> The frequency of the radiation is 33.9 THz
<u>Explanation:</u>
We are given:
Wave number of the radiation,
Wave number is defined as the number of wavelengths per unit length.
Mathematically,
where,
= wave number =
= wavelength of the radiation = ?
Putting values in above equation, we get:
Converting this into meters, we use the conversion factor:
1 m = 100 cm
So,
- The relation between frequency and wavelength is given as:
where,
c = the speed of light =
= frequency of the radiation = ?
Putting values in above equation, we get:
Converting this into tera Hertz, we use the conversion factor:
So,
Hence, the frequency of the radiation is 33.9 THz