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3 years ago

What is the WATER concentration in 1 liter of a solution that contains 2 moles of ions? (NOT the ion concentration)

Chemistry

1 answer:

blsea [12.9K]3 years ago

6 0

<u>Answer:</u> The concentration of water is 1 M

<u>Explanation:</u>

We are given:

Moles of ions a solution contains = 2 moles

The chemical equation for the ionization of water follows:

$H_2O\rightarrow H^++OH^-$

From the above equation:

2 moles of total ions are produced by 1 mole of water

To calculate the molarity of solution, we use the equation:

$\text{Molarity of the solution}=\frac{\text{Moles of solute}}{\text{Volume of solution (in L)}}$

Moles of water = 1 mol

Volume of solution = 1 L

Putting values in above equation, we get:

$\text{Molarity of }H_2O=\frac{1mol}{1L}\\\\\text{Molarity of }H_2O=1M$

Hence, the concentration of water is 1 M

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Answer: The volume of the new solution is 83.33 mL.

Explanation:

Given: $V_{1}$ = 200 mL, $M_{1}$ = 0.5 M

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Formula used to calculate the volume of new solution is as follows.

$M_{1}V_{1} = M_{2}V_{2}$

Substitute the values into above formula as follows.

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Explanation : Given,

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As we known that at equivalent point, the moles of $HC_2H_5CO_2$ and KOH are equal.

So, Moles of KOH = Moles of $HC_2H_5CO_2$ = 0.0422 mol

Now we have to calculate the volume of KOH.

$\text{Volume of }KOH=\frac{\text{Moles of }KOH}{\text{Concentration of }KOH}$

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Total volume of solution = 0.220 L + 0.00754 L = 0.22754 L

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$HC_2H_5CO_2+KOH\rightleftharpoons C_2H_5CO_2K+H_2O$

Moles of $C_2H_5CO_2K$ = 0.0422 mol

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$pH=\frac{1}{2}[14+4.89+\log (0.1855)]$

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