Question

A system expands from a volume of 1.00 l to 2.00 l against a constant external pressure of 1.00 atm. what is the work (w) done by the system? (1 l·atm = 101.3 j)

Answer 1

The work done by a system kept at constant pressure is given by:
$W=p \Delta V = p (V_f - V_i)$
where
p is the pressure
$V_f$ is the final volume
$V_i$ is the initial volume

If we plug the numbers given by the problem into this equation, we find
$W=p (V_f -V_i)=(1.00 atm)(2.00 L-1.00 L)=1.00 L\cdot atm$

And since $1 atm \cdot L = 101.3 J$, we have that the work done is
$W= 1.00 atm \cdot L = 101.3 J$

Answer 2

The work done by the system is about 101.3 J

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Further explanation

Let's recall Work Done by Ideal Gas formula as follows:

$\boxed{ W = \int {P} \, dV }$

where:

P = Gas Pressure ( Pa )

V = Gas Volume ( m³ )

Let us now tackle the problem!

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Given:

initial volume of system = Vo = 1.00 L

final volume of system = V = 2.00 L

constant external pressure = P = 1.00 atm

Asked:

work done by the system = W = ?

Solution:

$W = \int {P} \, dV$

$W = P \Delta V$ ← Constant External Pressure

$W = P ( V - V_o )$

$W = 1.00 ( 2.00 - 1.00 )$

$W = 1.00 ( 1.00 )$

$W = 1.00 \texttt{ L.atm}$

$W = 1.00 \times 101.3 \texttt{ J}$ ← Convert from L.atm to Joule

$\boxed {W = 101.3 \texttt{ J} }$

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Conclusion:

The work done by the system is about 101.3 J

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Learn more

• Buoyant Force : brainly.com/question/13922022

• Kinetic Energy : brainly.com/question/692781

• Volume of Gas : brainly.com/question/12893622

• Impulse : brainly.com/question/12855855
• Gravity : brainly.com/question/1724648

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Answer details

Grade: High School

Subject: Physics

Chapter: Pressure