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Goryan [66]
3 years ago
12

Physics is explicitly involved in studying which of these activities?

Physics
2 answers:
Dmitrij [34]3 years ago
8 0
Hey Friends
The answer to this question would be C
Hope i helped 
~Katie 
Katarina [22]3 years ago
6 0

Answer:

Option (C)

Explanation:

Physics is the study of measurement of different physical quantities.

The motion of a spacecraft under the gravitational influence, is due to the several forces acting on spacecraft.

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Explain a situation in which you can accelerate even thought your speed doesn’t change
Juli2301 [7.4K]

Explanation:

An object's acceleration is the rate its velocity (speed and direction) changes. Therefore, an object can accelerate even if its speed is constant - if its direction changes. ... Light's acceleration is zero. Since it travels in a straight line, its direction does not change.

7 0
3 years ago
Find the angle between two equal forces (p) when their resultant is equal to (p)<br>​
Alexus [3.1K]

Answer:

60°

Explanation:

It will be equilateral triangle, you can prove with the cosine theorem.

1)P^2=P^2+P^2 - 2×P×P× cos A

2) cos A= P^2 / 2× P^2 = 1/2

cos A = 1/2

A = 60°

If you wrote this question right,it will be solved like this :)

4 0
2 years ago
Read 2 more answers
To determine the speed of a wave, you would use which of the following formulas?
vovangra [49]
Speed = wavelength x frequency determine the speed of a wave,
4 0
2 years ago
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A proton is accelerated to 225V. Its de-Broglie wavelength is:
marin [14]

Answer:

The  value  is  \lambda =  1.9109 *10^{-12} \  m

Explanation:

From the question we are told that

  The  potential of the proton is  V  =  225 \  V

Generally the momentum of the particle is mathematically represented as

         p  =  \sqrt{ 2 *  m  *  V  *  e }

Here  e is the charge on the proton with value  

       e =  1.60 *10^{-19} \  C

      m is the mass of the proton with value  m  =  1.67 *10^{-27} \  kg

So

    p  =  \sqrt{ 2 * (1.67*10^{-27} ) *  225 *  1.6*10^{-19}}

=>    p  = 3.4676 *10^{-22} \  kg \cdot m/ s

So the de-Broglie wavelength isis mathematically represented as

     \lambda  =  \frac{h}{p}

Here  h is the Planck's  constant with value  

       h = 6.626 *10^{-34} \  J\cdot s

=>   \lambda  =  \frac{6.626 *10^{-34}}{3.4676 *10^{-22} }

=>\lambda =  1.9109 *10^{-12} \  m

   

6 0
3 years ago
A very strong, but inept, shot putter puts the shot straight up vertically with an initial velocity of 12.0 m/s. how long does h
Lunna [17]

The shot has a constant downward acceleration of a_y=-9.81\,\dfrac{\mathrm m}{\mathrm s^2}. Since acceleration is constant, the velocity of the ball is given by

a_y=\dfrac{v_y-v_{0y}}t

where v_y is the shot's vertical velocity at time t and v_{0y} is its initial vertical velocity. We're given that v_{0y}=12.0\,\dfrac{\mathrm m}{\mathrm s}. So

-9.81\,\dfrac{\mathrm m}{\mathrm s^2}=\dfrac{v_y-12.0\,\frac{\mathrm m}{\mathrm s}}t\implies v_y=12.0\,\dfrac{\mathrm m}{\mathrm s}+\left(-9.81\,\dfrac{\mathrm m}{\mathrm s^2}\right)t

gives the shot's velocity at time t.

Because acceleration is constant, we also know that

\bar v_y=\dfrac{d_y-d_{0y}}t=\dfrac{v_y+v_{0y}}2

where \bar v_y is the average vertical velocity, d_y is the vertical displacement at time t, and d_{0y} is the initial displacement at t=0. We're given an initial displacement of d_{0y}=2.10\,\mathrm m, so the displacement of the shot is

d_y=d_{0y}+\dfrac12(v_y+v_{0y})t=d_{0y}+v_{0y}t+\dfrac12a_yt^2

\implies d_y=2.10\,\mathrm m+\left(12.0\,\dfrac{\mathrm m}{\mathrm s}\right)t+\dfrac12\left(-9.81\,\dfrac{\mathrm m}{\mathrm s^2}\right)t^2

The shotputter is 1.90 m tall, a difference of 0.20 m from the initial height of the throw. So we want to find the time for the ball to reach a displacment of -0.20 m:

-0.20\,\mathrm m=2.10\,\mathrm m+\left(12.0\,\dfrac{\mathrm m}{\mathrm s}\right)t+\dfrac12\left(-9.81\,\dfrac{\mathrm m}{\mathrm s^2}\right)t^2

\implies t=2.63\,\mathrm s

4 0
3 years ago
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