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Goryan [66]
4 years ago
12

Physics is explicitly involved in studying which of these activities?

Physics
2 answers:
Dmitrij [34]4 years ago
8 0
Hey Friends
The answer to this question would be C
Hope i helped 
~Katie 
Katarina [22]4 years ago
6 0

Answer:

Option (C)

Explanation:

Physics is the study of measurement of different physical quantities.

The motion of a spacecraft under the gravitational influence, is due to the several forces acting on spacecraft.

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A 4kg watermelon is dropped from a height of 45m. What is the velocity of the watermelon just before it hits the ground?
Makovka662 [10]

Answer:

v=30 m/s

Explanation:

h - height

g - acceleration due to gravity=10

t - time

v- velocity

h =  \frac{1}{2}  \times g \times t {}^{2}

45 = 5t²

t² = 9

t=3 seconds

v=g×t

v=10×3

v=30 m/s

3 0
3 years ago
Jose throws a ball at 92 mi/hr horizontally. If there were NO air resistance, how
Trava [24]

Answer:

It should be 92 mi/h

Explanation:

Because there is no air resistance there is nothing pushing against it to slow it down, so only the initial force and gravity are acting on the ball

7 0
4 years ago
What would be the effect of the uneven distribution of
Marianna [84]
The equator would be warmer than the poles. :)
4 0
3 years ago
Read 2 more answers
Calculate the pressure exerted by 11.1 moles of neon gas in a volume of 5.45 L at 25°C using (a) the ideal gas equation and (b)
Ilia_Sergeevich [38]

Answer:

49.82414 atm

50.74675 atm

Explanation:

P = Pressure

V = Volume = 5.45 L

R = Gas constant = 0.08205 L atm/mol K

T = Temperature = 25°C

a = 0.211 atm L²/mol²

b = 0.0171 atm L²/mol²

From ideal gas law we have

PV=nRT\\\Rightarrow P=\dfrac{nRT}{V}\\\Rightarrow P=\dfrac{11.1\times 0.08205(273.15+25)}{5.45}\\\Rightarrow P=49.82414\ atm

The pressure is 49.82414 atm

From Van der Waals equation we have

\left(P+\frac{an^2}{V^2}\right)\left(v-nb\right)=nRT\\\Rightarrow P=\dfrac{nRT}{V-nb}-\dfrac{an^2}{V^2}\\\Rightarrow P=\dfrac{11.1\times 0.08205\times (273.15+25)}{5.45-(11.1\times 0.0171)}-\dfrac{0.211\times 11.1^2}{5.45^2}\\\Rightarrow P=50.74675\ atm

The pressure is 50.74675 atm

3 0
3 years ago
A person hits a tennis ball with a mass of 0.058 kg against a wall.
horrorfan [7]

Explanation:

Mass of the ball, m = 0.058 kg

Initial speed of the ball, u = 11 m/s

Final speed of the ball, v = -11 m/s (negative as it rebounds)

Time, t = 2.1 s

(a) Let F is the average force exerted on the wall. It is given by :

F=\dfrac{m(v-u)}{t}

F=\dfrac{0.058\times (11-(-11))}{2.1}

F = 0.607 N

(b) Area of wall, A=3\ m^2

Let P is the average pressure on that area. It is given by :

P=\dfrac{F}{A}

P=\dfrac{0.607\ N}{3\ m^2}

P = 0.202 Pa

Hence, this is the required solution.

8 0
3 years ago
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