Answer:
a)
Explanation:
- A block sliding down an inclined plane, is subject to two external forces along the slide.
- One is the component of gravity (the weight) parallel to the incline.
- If the inclined plane makes an angle θ with the horizontal, this component (projection of the downward gravity along the incline, can be written as follows:

(taking as positive the direction of the movement of the block)
- The other force, is the friction force, that adopts any value needed to meet the Newton's 2nd Law.
- When θ is so large, than the block moves downward along the incline, the friction force can be expressed as follows:
- The normal force, adopts the value needed to prevent any vertical movement through the surface of the incline:
- In equilibrium, both forces, as defined in (1), (2) and (3) must be equal in magnitude, as follows:

- As the block is moving, if the net force is 0, according to Newton's 2nd Law, the block must be moving at constant speed.
- In this condition, the friction coefficient is the kinetic one (μk), which can be calculated as follows:

Answer:
you have to post the diagram with your question together cause we are to use the diagram to answer the question. Post the Diagram we are to ANSWER from. i really want to help
Line - A: (15/10) = 1.5 inch/second
Line - B: (0/10) = 0
Line - C: (10/10) = 1.0 inch/second
Line - D: (-25/20) = -1.25 inch/second
<em>Line-A</em> represents the greatest speed.
ALL of the quantities are unknown, because you haven't bothered to tell us anything that's known.