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bixtya [17]
3 years ago
11

A strong acid is neutralized with a weak base put at equal concentrations what can be said about this reaction? A. it will requi

re a larger quantity of base. B. the ph will need to reach 8.0 to be considered neutral. C. it will require a smaller quantity of base D. the base must first be diluted before it can be used to neutralize the acid​
Chemistry
2 answers:
Allushta [10]3 years ago
5 0

Answer:

A) it will require a larger quantity of base is correct

Explanation:

I got it right in class!

<em>Hope this Helps!! :))</em>

gavmur [86]3 years ago
4 0
A. it will require a larger quantity of base.
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Which of these is a mixture??<br><br> A.) salad<br> B.) potassium<br> C.) water<br> D.) sugar
tensa zangetsu [6.8K]
Salad would be a mixture because it is not chemically combined, if needed you could physically take it apart. So your answer would be A.)
8 0
4 years ago
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5.0x10^4mg to kg and answer in scientific notation
Elis [28]
5.0x10^1 kg is the correct answer
3 0
4 years ago
Question 5
seropon [69]

Answer:

0.128 g

Explanation:

Given data:

Volume of gas = 146.7 cm³

Pressure of gas = 106.5 Kpa

Temperature of gas = 167°C

Mass of oxygen gas = ?

Solution:

Volume of gas = 146.7 cm³ (146.7 /1000 = 0.1467 L)

Pressure of gas = 106.5 Kpa (106.5/101 = 1.1 atm)

Temperature of gas = 167°C (167 +273.15 = 440.15 K)

PV = nRT

P= Pressure

V = volume

n = number of moles

R = general gas constant = 0.0821 atm.L/ mol.K  

T = temperature in kelvin

n = PV/RT

n = 1.1 atm× 0.1467 L / 0.0821 atm.L/ mol.K   × 440.15 K

n = 0.1614 / 36.14 /mol

n = 0.004 mol

Mass of oxygen:

Mass = number of moles × molar mass

Mass = 0.004 mol × 32 g/mol

Mass = 0.128 g

6 0
3 years ago
In a titration experiment a student uses 1.4 m hbr solution and the indicator phenolphthalein to determine the concentration of
Likurg_2 [28]
The question is incomplete. Complete question is attached below:
...........................................................................................................................

Answer: 
Given: conc. of HBr = 1.4 M
Volume of HBr = 15.4 mL
Volume of KOH = 22.10 mL

We know that, M1V1 = M2V2
                        (HBr)      (KOH)

Therefore, M2 = M1V1/V2
                        = 1.4 X 15.4/22.10
                        = 0.9756 M

Concentration of KOH is 0.9756 M.

3 0
3 years ago
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How many molecules are there in 223 grams of Na2SO4?
Harlamova29_29 [7]
<h3><u>Answer;</u></h3>

= 9.45 × 10^23 molecules

<h3><u>Explanation; </u></h3>

The molar mass of Na2SO4 = 142.04 g/mol

Number of moles = mass/molar mass

                             = 223/142.04

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But;

1 mole = 6.02 × 10^23 molecules

Therefore;

1.57 moles = ?

= 1.57 × 6.02 × 10^23 molecules

<u>= 9.45 × 10^23 molecules </u>

8 0
3 years ago
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