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Anni [7]
3 years ago
15

In a titration experiment a student uses 1.4 m hbr solution and the indicator phenolphthalein to determine the concentration of

a koh solution.

Chemistry
2 answers:
Romashka-Z-Leto [24]3 years ago
6 0

shout out to the guy who helped  out of every1 by finding the correct question and answering

Likurg_2 [28]3 years ago
3 0
The question is incomplete. Complete question is attached below:
...........................................................................................................................

Answer: 
Given: conc. of HBr = 1.4 M
Volume of HBr = 15.4 mL
Volume of KOH = 22.10 mL

We know that, M1V1 = M2V2
                        (HBr)      (KOH)

Therefore, M2 = M1V1/V2
                        = 1.4 X 15.4/22.10
                        = 0.9756 M

Concentration of KOH is 0.9756 M.

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What is the concentration (in M) of a sample of the unknown dye with an absorbance of 0.25 at 542 nm?
Sladkaya [172]

Answer:

see explanation below

Explanation:

Question is incomplete, so in picture 1, you have a sample of this question with the missing data.

Now, in general terms, the absorbance of a substance can be calculated using the beer's law which is the following:

A = εlc

Where:

ε: molar absortivity

l: distance of the light in solution

c: concentration of solution

However, in this case, we have a plot line and a equation for this plot, so all we have to do is replace the given data into the equation and solve for x, which is the concentration.

the equation according to the plot is:

A = 15200c - 0.018

So solving for C for an absorbance of 0.25 is:

0.25 = 15200c - 0.018

0.25 + 0.018 = 15200c

0.268 = 15200c

c = 0.268/15200

c = 1.76x10⁻⁵ M

5 0
2 years ago
The concentration of an additive in a standard sample of palm oil was measured 6 times and the following results were obtained:
Lerok [7]

In the data, 0.20 ppm is an outlier and this can be rejected if there is a 95% confidence level.

<h3>What is an outlier?</h3>

When analyzing data an outlier is a value that is abnormal or too different from other data. In the case presented 0.20 can be tagged as an outlier because other values such as 0.11, 0.12, 0.13, and 0.14 are similar while 0.20 is outside this range.

<h3>Should this piece of data be rejected?</h3>

The general rule is that if there is a 95% of confidence or higher you can reject an outlier, knowing the other data occurs 95% of the time, and therefore the outlier is improbable.

Based on this, you can reject an outlier if the confidence level is 95%.

Learn more about outlier in: brainly.com/question/9933184

7 0
2 years ago
Is aluminum flammable
VashaNatasha [74]
Yes, aluminum is flammable
3 0
3 years ago
Read 2 more answers
A balloon contains 2.0 L of air at 101.5 kPa . You squeeze the balloon to a volume of 0.25 L.
8_murik_8 [283]
<h3>Answer:</h3>

812 kPa

<h3>Explanation:</h3>
  • According to Boyle's law pressure and volume of a fixed mass are inversely proportional at constant absolute temperature.
  • Mathematically, P\alpha \frac{1}{V}

At varying pressure and volume;

P1V1=P2V2

In this case;

Initial volume, V1 = 2.0 L

Initial pressure, P1 = 101.5 kPa

Final volume, V1 = 0.25 L

We are required to determine the new pressure;

P2=\frac{P1V1}{V2}

Replacing the known variables with the values;

P2=\frac{(101.5)(2.0L)}{0.25L}

           = 812 kPa

Thus, the pressure of air inside the balloon after squeezing is 812 kPa

8 0
2 years ago
To protect itself from herbivores, plants ______
9966 [12]
C.) both secrete toxins and have thorns (It simply depends on what kind of plant it is)
3 0
3 years ago
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