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Anni [7]
3 years ago
15

In a titration experiment a student uses 1.4 m hbr solution and the indicator phenolphthalein to determine the concentration of

a koh solution.

Chemistry
2 answers:
Romashka-Z-Leto [24]3 years ago
6 0

shout out to the guy who helped  out of every1 by finding the correct question and answering

Likurg_2 [28]3 years ago
3 0
The question is incomplete. Complete question is attached below:
...........................................................................................................................

Answer: 
Given: conc. of HBr = 1.4 M
Volume of HBr = 15.4 mL
Volume of KOH = 22.10 mL

We know that, M1V1 = M2V2
                        (HBr)      (KOH)

Therefore, M2 = M1V1/V2
                        = 1.4 X 15.4/22.10
                        = 0.9756 M

Concentration of KOH is 0.9756 M.

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The molecular weight of silver bromide (AgBr) is 187.77 g/mole. The presence of the ions in solution can be shown as- AgBr (insoluble) ⇄Ag^{+} + Br^{-1}.

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