In a titration experiment a student uses 1.4 m hbr solution and the indicator phenolphthalein to determine the concentration of
a koh solution.
2 answers:
The question is incomplete. Complete question is attached below:
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Answer:
Given: conc. of HBr = 1.4 M
Volume of HBr = 15.4 mL
Volume of KOH = 22.10 mL
We know that, M1V1 = M2V2
(HBr) (KOH)
Therefore, M2 = M1V1/V2
= 1.4 X 15.4/22.10
= 0.9756 M
Concentration of KOH is 0.9756 M.
...........................................................................................................................
Answer:
Given: conc. of HBr = 1.4 M
Volume of HBr = 15.4 mL
Volume of KOH = 22.10 mL
We know that, M1V1 = M2V2
(HBr) (KOH)
Therefore, M2 = M1V1/V2
= 1.4 X 15.4/22.10
= 0.9756 M
Concentration of KOH is 0.9756 M.
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Given:
The reaction between nitrogen gas and hydrogen gas.
To find:
Bonds on the reactant side
Solution:
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The bond between nitrogen atoms in single molecule = N≡N (triple bond)
Then in two molecules = 2 N≡N (triple bonds)
The bond between hydrogen atoms in single molecule = H-H (single bond)
Then in three molecules = 3 H-H (single bonds)
Product in the reaction =
The bonds between nitrogen and hydrogen atoms in single molecule = 3 N-H (single bond)
Then in two molecules = 6 N-H (single bonds)
So, there are two N≡N bonds and three H–H bonds are in reactants.
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Answer:
ii.
Explanation:
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From the given options:-
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has 6 electrons.