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Alex73 [517]
3 years ago
6

Determine the mass of a gold bar that has a density of 19.3 g/cm3 and is 4.72 cm high by 8.21 cm long by 3.98 cm deep.

Chemistry
1 answer:
TEA [102]3 years ago
5 0
The density of the gold is 19.3 grams/cc so each cc weighs 19.3grams. Now we can obtain the volume of gold from the given dimensions ie 4.72x8.21x3.98= 154.23 cc. So for the answer, just multiply the volume or 154.23 x 19.3= 2976.6 grams is the answer.
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How would you separate a mixture of alcohol and water
Kisachek [45]
You can use fractional distillation
4 0
3 years ago
4) Calculate the percentage by<br> mass of oxygen in Pb(NO3)2<br> A) 193<br> B20<br> 145
Ierofanga [76]

Answer:

  im getting 331.23

Explanation:

Element Number Mass Percet Composition

O            6         16.00  28.9828819853274

N             2         14.01 8.45937867946744

Pb             1        207.21 62.5577393352051

5 0
3 years ago
A 47.1 g sample of a metal is heated to 99.0°C and then placed in a calorimeter containing 120.0 g of water (c = 4.18 J/g°C) at
wlad13 [49]

Answer : The metal used was iron (the specific heat capacity is 0.44J/g^oC).

Explanation :

In this problem we assumed that heat given by the hot body is equal to the heat taken by the cold body.

q_1=-q_2

m_1\times c_1\times (T_f-T_1)=-m_2\times c_2\times (T_f-T_2)

where,

C_1 = specific heat of metal = ?

C_1 = specific heat of water = 4.18J/g^oC

m_1 = mass of metal = 47.1 g

m_2 = mass of water = 120 g

T_f = final temperature of water = 24.5^oC

T_1 = initial temperature of metal = 99^oC

T_2 = initial temperature of water = 21.4^oC

Now put all the given values in the above formula, we get

47.1g\times c_1\times (24.5-99)^oC=-120g\times 4.18J/g^oC\times (24.5-21.4)^oC

c_1=0.44J/g^oC

Form the value of specific heat of metal, we conclude that the metal used in this was iron.

Therefore, the metal used was iron (the specific heat capacity is 0.44J/g^oC).

3 0
3 years ago
In Part A, we saw that the theoretical yield of aluminum oxide is 0.700 mol . Calculate the percent yield if the actual yield of
s2008m [1.1K]

Considering the definition of percent yield, the percent yield is 76%.

<h3>Percent yield</h3>

The percent yield is the ratio of the actual return to the theoretical return expressed as a percentage.

The percent yield is calculated as the experimental yield divided by the theoretical yield multiplied by 100%:

percent yield=\frac{actual yield}{theorical yield}x100

where the theoretical yield is the amount of product acquired through the complete conversion of all reagents in the final product, that is, it is the maximum amount of product that could be formed from the given amounts of reagents.

<h3>Percent yield in this case</h3>

In this case, you know:

  • actual yield= 0.532 moles
  • theorical yield= 0.700 moles

Replacing in the definition of percent yield:

percent yield=\frac{0.532 moles}{0.700 moles}x100

Solving:

<u><em>percent yield= 76%</em></u>

Finally, the percent yield is 76%.

Learn more about percent yield:

brainly.com/question/14408642

#SPJ1

3 0
2 years ago
Which of the following refers to a chemical property
LuckyWell [14K]
Reactivity<span> refers to a chemical property </span>
8 0
4 years ago
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