The right answer is 2 divisions.
Meiosis follows the replication of DNA from a reproductive cell (male or female). It allows the passage of a so-called diploid mother cell to 2n chromosome homologous chromosomes to 4 single-chromosome haploid daughter cells. For that it must pass by two successive divisions, the first division is reductionelle generating two diploid cells with n chromosomes. the second division is equational giving 4 haploid cells to n chromosomes from the two preceding cells.
Answer:
C. The enzyme with mutation 1 has decreased affinity for pyridoxal phosphate, whereas the enzyme with mutation 2 has lost the ability to bind to the substrates.
Explanation:
A coenzyme is an organic cofactor that binds with an enzyme in order to initiate or aid the function of the enzyme. A coenzyme binds to the active site of the enzyme (where the reaction occurs), thereby triggering its activation by modifying protein structure during the reaction. Some examples of coenzymes include Coenzyme A and Adenosine triphosphate (ATP). Pyridoxal phosphate is a coenzyme (it is the active form of vitamin B6) that is required for the function of cystathionase. Moreover, cystathionase is an enzyme that enables cells the synthesis of cysteine from methionine (transsulfuration pathway). The binding of pyridoxal phosphate to the enzyme increases the binding affinity of the enzyme for the substrate, thereby influencing its activity. In this case, it is expected that mutation 1 reduces the binding affinity of the enzyme to the cofactor, and thereby the cofactor is required at a higher concentration to restore normal enzyme activity.
<span>crushing a can.
melting an ice cube.
boiling water.
mixing sand and water.
breaking a glass.dissolving sugar and water
.shredding paper.
<span>chopping wood.</span></span>
