1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Zanzabum
2 years ago
11

The amount to which $5,000 would grow in ten years at 6% compounded semiannually.

Mathematics
2 answers:
Tema [17]2 years ago
7 0

Answer:

Amount = $ 9030.56

Step-by-step explanation:

Given: Principal value, P = $ 5000

          Rate, R = 6%

          Time, T = 10 years

To find: Amount when compounded semiannually

Semiannual means half yearly which implies interest to be calculated twice in a year.

\implies R=\frac{6}{2}=3 %

n ( no. of times interest to be applied ) = 2 × 10 = 20

using compound interest formula of calculating amount we get,

A=P\times(1+\frac{R}{100})^n

A=5000\times(1+\frac{3}{100})^{20}

A=5000\times(\frac{103}{100})^{20}

A=5000\times1.80611123467

A=9030.55617335

⇒ A = $ 9030.56

Therefore, Amount = $ 9030.56

melomori [17]2 years ago
4 0
A=p(1+i/k)^kn
A=5000(1+0.06/2)^2*10
A=9,030.56
You might be interested in
Kelsey had $65 to spend on books. Each book cost $5.50, and there was a $7.50 fee for shipping. She let b equal the number of bo
xeze [42]

Answer: Kelsey had $65 to spend on books. Each book cost $5.50, and there was a $7.50 fee for shipping. She let b equal the number of books she can purchase

Step-by-step explanation:

3 0
1 year ago
NEED HELP PLSSSS I DONT KNOW THE ANSWER
Lorico [155]

Answer:

[ 3 , ∞ ) Set-Builder Notation:

{ x | x ≥ 3 }

Step-by-step explanation:

7 0
3 years ago
For the equation ae^ct=d, solve for the variable t in terms of a,c, and d. Express your answer in terms of the natural logarithm
saveliy_v [14]

We have been given an equation ae^{ct}=d. We are asked to solve the equation for t.

First of all, we will divide both sides of equation by a.

\frac{ae^{ct}}{a}=\frac{d}{a}

e^{ct}=\frac{d}{a}

Now we will take natural log on both sides.

\text{ln}(e^{ct})=\text{ln}(\frac{d}{a})

Using natural log property \text{ln}(a^b)=b\cdot \text{ln}(a), we will get:

ct\cdot \text{ln}(e)=\text{ln}(\frac{d}{a})

We know that \text{ln}(e)=1, so we will get:

ct\cdot 1=\text{ln}(\frac{d}{a})

ct=\text{ln}(\frac{d}{a})

Now we will divide both sides by c as:

\frac{ct}{c}=\frac{\text{ln}(\frac{d}{a})}{c}

t=\frac{\text{ln}(\frac{d}{a})}{c}

Therefore, our solution would be t=\frac{\text{ln}(\frac{d}{a})}{c}.

5 0
3 years ago
PLEASE HELP ASAP!! (Find the surface area of the prism) SHOW WORK! (Number 6)
Leokris [45]
Sa= bw+hw+lw+\frac{1}{2}bh(2)
SA=(12*4)+(16*4)+(20*4)+( \frac{1}{2} 12*16*2)
SA= 28+64+80+(6*16*2)
SA=28+64+80+(96*2)
SA=28+64+80+192
SA=364cm^{2}
3 0
3 years ago
What is the exact value of sin 48 degrees?
poizon [28]
.7431448255...

i entered sin(48) into my calculator and got the answer above
7 0
2 years ago
Read 2 more answers
Other questions:
  • What is the next term in the following constant velocity sequence? 10cm, 17cm, 24cm, ...
    12·1 answer
  • I WILL GIVE BRAINLYIST IM BEING TIMED PLS HELP ASAP PLS PLS PLS PLS I WILL FAIL
    6·1 answer
  • What is the sixth term of the sequence an=-3•2n+1<br>a6=
    13·1 answer
  • Which Vertices have MULTIPLE EDGES?
    15·1 answer
  • Un mecánico tiene un conjunto de 20 llaves. La medida de la llave más grande es 3/4 pulgada, mientras que la llave mas pequeña e
    8·1 answer
  • HELP PLZZZZZZZZZZZZ PLZZZZZZZZZZZZ
    11·1 answer
  • This was useless because a selected the exact answers and they where all wrong :(
    7·2 answers
  • The waves created by two speed boats in a lake interact to form larger waves. This is an example of
    6·2 answers
  • If 22+4=24 13+6=16 80+2==82 then 67+9= what
    9·1 answer
  • What is the equation of the line in slope-intercept form that is perpendicular to line g and passes through the point (4, 2)? Sh
    12·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!