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Andrei [34K]
4 years ago
8

Which of the following statments do not describe the exspression 5 - 3c?

Mathematics
1 answer:
mina [271]4 years ago
4 0

Answer:

5 - 3 times c is the correct ans

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How do you solve this problem?
kykrilka [37]
You can multiply 8 times 9 to get 72 and then move the decimal over to the right to get the answer of 7.2
5 0
4 years ago
Using the letters in the word INNOVATIVE, find the number of permutations that can be formed using 4 letters at a time. Show you
lyudmila [28]

Answer:  1) 5040 and 2) 165

Step-by-step explanation:

1) Here total number of letters = 10

The number of permutations that can be formed using 4 letters at a time

= P (10, 4)

= 10_P_4

= \frac{10!}{(10-4)!}

=  \frac{10!}{6!}

= \frac{10\times 9\times 8\times 7\times 6!}{6!}

= 10 × 9 × 8 × 7

= 5040

2) Here the total number of machine = 11

The different combinations of machines can Geoff choose from to use

= 11_C_3

= \frac{11!}{(11-3)!3!}

= \frac{11!}{8!3!}

= \frac{11\times 10\times 9\times 8!}{8!\times 6}

= 11 × 5 × 3

= 165

5 0
3 years ago
1. Let the sample space represent all the values from 1 to 10. Let A = {1, 2, 8} and B = {2, 7}. What is the P(A ∩ B)?
AnnZ [28]

A \cap B denotes to all common elements in both A and B

  • Sample space=S={1,2,3,4,5,6,7,8,9,10}

So

  • A={1,2,8}
  • B={2,7}

2 is common

Hence

A $\cap$ B={2}

7 0
2 years ago
Read 2 more answers
-20:2+(15)=<br> Simplify
alukav5142 [94]

Answer:

5

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
Tim explained a function in words and Paul wrote an equation. Tim The amount of money in Marshas savings account increases at a
soldier1979 [14.2K]

Answer:

Tim has the smaller y-intercept = 2780

Step-by-step explanation:

Tim explains that Marshas saving increases by 225 per month. After 8 months, Marsha's has 4580 in his account.

Let m be the gradient(change per month)

Let y be the initial money in Marsha's account.

Let y1 be the amount in Marsha's account after 8 months

y1 = 4580

Let x be the initial month d money was put into the account.

Let x1 be the number of months it takes for money to increase to 4580

x1= 8

(y - y1) /(x - x1) = m

(y - 4580)/ (x - 8) = 225

y - 4580 = 225(x - 8)

y - 4580 = 225x - 1800

y = 225x - 1800 + 4580

y = 225x + 2780

Comparing with y = mx + c, c(intercept) = 2780

For Paul,

y - 1400 = 56(x + 26)

y -1400 = 56x + 1456

y = 56x + 1456 + 1400

y = 56x + 2856

Comparing with y = mx + c, c(intercept) = 2850

Therefore comparing Tim's Y intercept and Paul's Y intercept,

2780 < 2856

Tim's function smaller y intercept = 2780

7 0
3 years ago
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