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Sergio [31]
3 years ago
8

Describe the application of Pascal's law in hydraulic excavator.plz help me ​

Physics
1 answer:
Nuetrik [128]3 years ago
3 0

Explanation:

The hydraulic system works on the principle of Pascal's law which says that the pressure in an enclosed fluid is uniform in all the directions. ... As the pressure is same in all the direction, the smaller piston feels a smaller force and a large piston feels a large force.

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Six automobiles are initially traveling at the indicated velocities. The automobiles have different masses and velocities. The d
pishuonlain [190]

Answer:

Ranking the cars based on magnitude of momentum <em>(largest to smallest)</em>:

1. Purple, Light Blue

2. Red, Yellow, Blue

3. Green

Explanation:

Based on the given parameters ( mass and velocity), we can calculate the momentum of the various cars using the formula:

momentum = mass x velocity

1. Momentum of red car = 1000kg x 10m/s = 10,000Kgm/s

2. Momentum of Yellow car = 2000kg x 5m/s = 10,000Kgm/s

3. Momentum of blue car = 500kg x 20m/s = 10,000Kgm/s

4. Momentum of light blue car = 1000kg x 20m/s = 20,000Kgm/s

5. Momentum of green car = 500kg x 10m/s = 5,000Kgm/s

6. Momentum of purple car = 4000kg x 5m/s = 20,000Kgm/s

Hence,

Ranking the  based on magnitude of momentum <em>(largest to smallest)</em> we have:

1. Purple, Light Blue

2. Red, Yellow, Blue

3. Green

8 0
3 years ago
Determination of Thermal Conductivity. In determining the thermal conductivity of an insulating material, the temperatures were
Goshia [24]

Answer:

k=0.0577w/mk

k=0.03338BTU/h-ft-ºF

Explanation:

First we use the equation for heat transfer by conduction and solve for K

Q=KA(T2-T1)/x

Where

q=heat

A=area

T=temperature

K=conductivity

x=thickness

solving for k

k=Qx/A(T2-T1)

Q/A=Heat flux=q

k=qx/(T2-T1)

k=35.1*0.025/(318.4-303.2)

K=0.0577w/mk

remember that 1 btu / hftk equals 1,729 w / mk

K=0.0577/1.729=0.03338BTU/h-ft-ºF

3 0
3 years ago
Learning Check: Ranking Elements
loris [4]
Yes
62748476182973838292
8 0
3 years ago
What is the period of oscillation for a pendulum that completes 3.00 cycles every 2.00 s?
torisob [31]

Answer:

\huge\boxed{\sf T = 0.67\ seconds}

Explanation:

<u>Given Data:</u>

Cycles = c = 3 cycles

Time = t = 2 seconds

<u>Required:</u>

Time period = T = ?

<u>Formula:</u>

1) f = c/t

2) T = 1/f

<u>Solution:</u>

<u>Finding frequency first:</u>

f = c / t

f = 3/2

f = 1.5 Hz

<u>Now, finding period:</u>

T = 1/f

T = 1 / 1.5

T = 0.67 seconds

\rule[225]{225}{2}

6 0
3 years ago
A horizontal spring is lying on a frictionless surface. One end of the spring is attaches to a wall while the other end is conne
JulsSmile [24]

Answer:

v_f = 1.05 m/s

Explanation:

From conservation of energy;

E_f = E_i

Thus,

(1/2)m(v_f)² + (1/2)I(ω_f)² + m•g•h_f + (1/2)k•(x_f)² = (1/2)m(v_i)² + (1/2)I(ω_i)² + m•g•h_i + (1/2)k•(x_i)²

This reduces to;

(1/2)m(v_f)² + (1/2)Ik(x_f)² = (1/2)k•(x_i)²

Making v_f the subject, we have;

v_f = [√(k/m)] * [√((x_i)² - (x_f)²)]

We know that ω = √(k/m)

Thus,

v_f = ω[√((x_i)² - (x_f)²)]

Plugging in the relevant values to obtain;

v_f = 17.8[√((0.068)² - (0.034)²)]

v_f = 17.8[0.059] = 1.05 m/s

3 0
3 years ago
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