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aleksley [76]
4 years ago
13

What is a horizontal segment meaning on a position vs. time graph?

Physics
1 answer:
sergeinik [125]4 years ago
4 0

The velocity of the object is zero (the object is at rest)

Explanation:

A position vs time graph represents the motion of an object; in particular:

  • The position of the object x(t) is represented on the y-axis
  • The time t is represented on the x-axis

For a position-time graph, the slope of the graph is given by

m=\frac{\Delta x}{\Delta t}

where

\Delta x is the change in position

\Delta t is the change in time

However, we see that this is equivalent to the definition of velocity:

v=\frac{\Delta x}{\Delta t}

Therefore, the slope of  a position-time graph is equivalent to the velocity of the object.

And so, a horizontal segment on a position vs time graph means that the object has zero velocity (because the slope is zero).

Learn more about velocity:

brainly.com/question/5248528

#LearnwithBrainly

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vi^{2}sin2thita/g =12^{2}sin2[30]/9.8=12.7Answer:

Explanation:

range is given as

6 0
3 years ago
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1. If a system is isolated, the total energy within that system is constant. Consider the case of a hot cup of coffee: when it c
nignag [31]

Answer:

1. B. The person and the Earth

2. This is because the energy gained by the person equals the energy lost by the earth,

Explanation:

1.

B. The person and the Earth

This is because the person and the earth both represent a system. A system consists of more than one item. A system consists of two or more items interacting with each other.

2. This is because, the energy of an isolated system is conserved according to the second law of thermodynamics which states that in an isolated system, energy can neither be created nor destroyed. So, there is an exchange of energy between the person and the Earth. So, the energy gained by the person at the new height equals the energy lost by the earth. And thus, the total energy of the system remains constant.

6 0
3 years ago
A net force of –8750N is used to stop of 1250.kg car travelling 25m/s. What braking distance is needed to bring the car to a hal
Karolina [17]

Answer:

d = 44.64 m

Explanation:

Given that,

Net force acting on the car, F = -8750 N

The mass of the car, m = 1250 kg

Initial speed of the car, u = 25 m/s

Final speed, v = 0 (it stops)

The formula for the net force is :

F = ma

a is acceleration of the car

a=\dfrac{F}{m}\\\\a=\dfrac{-8750}{1250}\\\\a=-7\ m/s^2

Let d be the breaking distance. It can be calculated using third equation of motion as :

v^2-u^2=2ad\\\\d=\dfrac{v^2-u^2}{2a}\\\\d=\dfrac{0^2-(25)^2}{2\times (-7)}\\\\d=44.64\ m

So, the required distance covered by the car is 44.64 m.

4 0
3 years ago
Reactance Frequency Dependence: Sketch a graph of the frequency dependence of a resistor, capacitor, and inductor. RLC Circuit R
jolli1 [7]

Answer:

f=\frac{1}{2\pi \sqrt{LC}}

Explanation:

We know that impedance of a RLC circuit is given by Z=R+J(X_L-X_C)

So Z=\sqrt{R^2+(X_L-X_C)^2} here R is resistance X_L is inductive reactance and X_C is capacitive reactance

To minimize the impedance X_L-X_C should be zero we know that X_L=\omega L\ and \ X_C=\frac{1}{\omega C}

So \omega L-\frac{1}{\omega C}=0

\omega ^2=\frac{1}{LC}

\omega =\sqrt{\frac{1}{LC}}

We know that \omega =2\pi f

So \omega =2\pi f=\frac{1}{\sqrt{LC}}

f=\frac{1}{2\pi \sqrt{LC}}

Where f is resonance frequency  

8 0
3 years ago
If a net force acts on an object the object will change speed, direction or shape
DanielleElmas [232]
Only the speed will change because it is in motion 
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4 years ago
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