Question

What is the period of oscillation for a pendulum that completes 3.00 cycles every 2.00 s?

Answer 1

Answer:

$\huge\boxed{\sf T = 0.67\ seconds}$

Explanation:

Given Data:

Cycles = c = 3 cycles

Time = t = 2 seconds

Required:

Time period = T = ?

Formula:

1) f = c/t

2) T = 1/f

Solution:

Finding frequency first:

f = c / t

f = 3/2

f = 1.5 Hz

Now, finding period:

T = 1/f

T = 1 / 1.5

T = 0.67 seconds

$\rule[225]{225}{2}$