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melomori [17]
1 year ago
9

an 0.45-kg object is being pulled with a tension force of 14.2 n at a constant velocity of 3.41 m/s. what is the force of fricti

on acting on the object?
Physics
1 answer:
Lisa [10]1 year ago
7 0

The forces of friction acting on the object are <u>12.67 N.</u>

<u />

Friction is the force resisting the relative motion of sturdy surfaces, fluid layers, and material factors sliding towards each specific. There are numerous styles of friction. Dry friction is a strain that opposes the relative lateral movement of two stable surfaces in touch.

<u>Calculation:-</u>

ma - 14.2 N = Friction force

14.2 N - 0.45 × 3.41 = <u>12.67 N</u>

Friction is the shape of contact pressure. It exists between the surfaces that are in touch. The frictional force relies upon the character of the floor in contact. The rougher the ground, the extra friction is involved. The frictional force is proportional to the urgent pressure, which is the burden of the body. it's miles impartial of the place of the touch.

Learn more about friction here:-brainly.com/question/24338873

#SPJ4

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4 years ago
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What is the total displacement of the car after 5 h? Question 4 options: 0 km 15 km 20 km 40km.
Likurg_2 [28]

Displacement can be defined as the overall change in the position of the object. The displacement of the car in 5 hrs is 0 km.

Displacement:

It is a vector quantity that is defined as the overall change in the position of the object.

The formula for displacement is:

s = s_f-s_i

Where,

s - total displacement

s_f - final position

s_i- initial position

In the given graph:

  • Car displaces 15 km in 2 hrs
  • Car displaces 20 km in 4 hrs.
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Therefore, the displacement of the car in 5 hrs is 0 km.

Learn more about Displacement:  

brainly.com/question/10919017

3 0
3 years ago
What are the conditions required for a rigid body to be in translational equilibrium?
kolezko [41]

Answer:

Explanation:

The condition for translation equilibrium is that is that the net force acting on the body must be zero.

The sum all the external forces acting on the body in horizontal as well as vertical direction must be zero.

∑Fₓ=0  and ∑Fy=0

now if the above two condition are satisfied the rigid body is said to be in  translational equilibrium.

God bless... hope this help to clear your doubt.

5 0
3 years ago
it is said that a fool and his money ate soon parted.Suppose we place the fool and gold brick in the middle of a frictionless,fr
Pavel [41]
He could theoretically push the gold brick away from himself, and due to Newton's 3rd law (Every action has an equal and opposite reaction), the same amount of force would recoil back at him from the gold brick. As a result, he will move in the opposite direction from the gold brick, and since it as an ideal frozen lake (meaning there is no friction present), he will keep going until he reaches the edge of the lake.

And I don't know if he's still a fool. That's up to you.
3 0
3 years ago
1. A physical quantity P is related to four observables a, b and c as follows: P= (a3b 2 /c4 ) The percentage errors of measurem
Ber [7]

Answer:

The percentage error in quantity P is 19%.

Explanation:

It is given that,

A physical quantity P is related to four observables a, b and c as follows:

P=\dfrac{a^3b^2}{c^4}

The percentage errors of measurements in a, b and c are 1%, 4% and 2% respectively.

We need to find the percentage error in quantity P. It is given by :

\dfrac{\Delta P}{P}\times 100=(3\times \dfrac{\Delta a}{a}+2\times \dfrac{\Delta b}{b}+4\times \dfrac{\Delta c}{c})\\\\=3\times 1+2\times 4+4\times 2\\\\\dfrac{\Delta P}{P}\times 100=19\%

So, the percentage error in quantity P is 19%.

6 0
3 years ago
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