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Sauron [17]
3 years ago
9

Help 60points algebra

Mathematics
1 answer:
Luba_88 [7]3 years ago
3 0

ANSWER:

  • x³ – 5x² + 3x – 15
  • x²(x – 5) + 3(x – 5)
  • (x² + 3)(x – 5)

So, <u>Correct choice</u> - [C] (x² + 3)(x – 5).

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A is a 4x4 matrix and A^2 + 4A - 5I = 0. If det(A+2I)&gt;0, enter det(A+2I)
maw [93]
\mathbf A^2+4\mathbf A-5\mathbf I=0
\implies\mathbf A^2+4\mathbf A+4\mathbf I=(\mathbf A+2\mathbf I)^2=9\mathbf I
\implies\det\bigg((\mathbf A+2\mathbf I)^2\bigg)=\det(9\mathbf I)
\implies\det(\mathbf A+2\mathbf I)^2=9^4\det\mathbf I
\implies\det(\mathbf A+2\mathbf I)=\pm\sqrt{9^4}
\implies\det(\mathbf A+2\mathbf I)=9^2=81

where we take the positive root because we're told that the determinant is positive.
5 0
3 years ago
Simplify 7x + 7 + 6x - 9.<br><br> 13x - 2<br> 13x + 2<br> 11x
nikklg [1K]
To do this you must combine like terms as follows.

7x + 6x = 13x
7 - 9 = -2 

Combine these together and you will get the following.

13 - 2 or -2 +13
7 0
3 years ago
Read 2 more answers
Consider a dart board made of three concentric circles of radii 1 cm, 2cm and 3 cm, respectively. The points you obtain by hitti
Vlada [557]

Answer:

The answer is 350 points

Step-by-step explanation:

The Area of a circle is πr∧2

The problem states that in the attempts, you never hit the outermost ring in the 10 attempts so we need the area of the 1cm and 2cm circles

Area of the 1st circle;  π X 1∧2 = π

Area of the Second circle; π X 2∧2 = 4π

We also need the area which is the difference between the area of the 1cm and 2cm circle

4π - π  = π

Points 50 = π/4π = 1/4

points 30 = 3π/4π = 3/4

For one attempt,

E(x) = 50 x 1/4 + 30 x 3/4

= 12.25 + 22.5

= 34.75

This is approximately 35

Therefor, 10 individual attempts will be 10 x 35 = 350

8 0
3 years ago
Read 2 more answers
!!!!!!!!!!!!!!!!!!!!
-Dominant- [34]
3. 152 i think that is it
7 0
3 years ago
This is very hard for me I need to know how to do it
insens350 [35]

The zeros of a function are the values of x that make the function be equal to zero.

When graphing a quadratic equation, the graph is a parabola, and the zeros of the function are the x-intercepts of the graph, which are the points where the graph intersects the x-axis.

So, if the zeros of this function are x = -8 and x = 2, that means the parabola crosses the x-axis at x = -8 and x = 2.

Therefore the correct option is the first one.

6 0
1 year ago
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