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Sauron [17]
3 years ago
9

Help 60points algebra

Mathematics
1 answer:
Luba_88 [7]3 years ago
3 0

ANSWER:

  • x³ – 5x² + 3x – 15
  • x²(x – 5) + 3(x – 5)
  • (x² + 3)(x – 5)

So, <u>Correct choice</u> - [C] (x² + 3)(x – 5).

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Log7 (-5k-3)=log7 -4k
exis [7]

Answer:

k = -3

Step-by-step explanation:

log7(-5k - 3) = log7 (-4k)

---> -5k - 3 = -4k

-k - 3 = 0

k = -3

5 0
3 years ago
[HELP] For j(x) = <img src="https://tex.z-dn.net/?f=5%5Ex%5E-%5E3" id="TexFormula1" title="5^x^-^3" alt="5^x^-^3" align="absmidd
Alina [70]

The difference quotient of the function that has been presented to us will turn out to be 5.

<h3>How can I calculate the quotient of differences?</h3>

In this step, we wish to determine the difference quotient for the function that was supplied.

To begin, keep in mind that the difference quotient may be calculated by:

Lim h->0 \frac{f(x+h)-f(x)}{h}

Now, for the purpose of the function, we need this:

Then we will have:

$$\begin{aligned}&\lim _{h \rightarrow 0} \frac{j(x+h)-j(x)}{h} \\&\lim _{h \rightarrow 0} \frac{5 *(x+h)-3-5 * x+3}{h} \\&\lim _{h \rightarrow 0} \frac{5 x+5 h-3-5 x+3}{h} \\&\lim _{h \rightarrow 0} \frac{5 h}{h}=5\end{aligned}$$

j(x) = 5x - 3

Then the following will be true:

Therefore, 5 is the value of the difference quotient for j(x) is %

Read the following if you are interested in finding out more about difference quotients:

brainly.com/question/15166834

#SPJ1

6 0
1 year ago
What is the value of y if 5/25 = y/5?
galina1969 [7]

Answer:

y=0.04

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
Express 72 as a percentage of 92
dolphi86 [110]
\frac{72}{92} * 100 = 78,2608%
78,26%
7 0
3 years ago
Read 2 more answers
The​ day's high temperature in St. Louis comma Missouri was recorded as 77 degrees' F. Use the formula Upper C=5/9(F-32) to writ
ludmilkaskok [199]

Answer:

The​ day's high temperature written as degrees Celsius is 25 degrees' Celsius.

Step-by-step explanation:

The​ day's high temperature in St. Louis ,Missouri was recorded as 77 degrees F.

We are supposed to find the​ day's high temperature written as degrees Celsius.

Formula : C=\frac{5}{9}(F-32)

Substitute the value of F is 77 degrees

So,C=\frac{5}{9}(77-32)

C=\frac{5}{9}(45)

C=25

Thus, The​ day's high temperature written as degrees Celsius is 25 degrees' Celsius.

6 0
3 years ago
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