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3 years ago

Which of the following is an example of a quadratic equation?

Mathematics

1 answer:

jasenka [17]3 years ago

5 0

Answer:

C) any eqaution that has a variable or number squared is a qaudratic equation

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(multiple choice) plz help me!!

harkovskaia [24]

$8 \sqrt{5} is \: the \: length$

Step-by-step explanation:

$( {16})^{2} = ( {x})^{2} - ( {8})^{2} \\ 256 = {x}^{2} - 64 \\ 256 + 64 = {x}^{2} \\ \sqrt{320} = \sqrt{ {x}^{2} } \\ 8 \sqrt{5} = x$

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3 years ago

The leftmost digits of rwo nunbers are 8 and 3 which one is greater

makvit [3.9K]

EIGHT WOULD BE GREATER

7 0

3 years ago

7. Use the quadratic formula to find the solution(s). x² + 2x - 8 = 0

morpeh [17]

Hey there!

Use the quadratic formula to find the solution(s). x² + 2x - 8 = 0

Answer :

x = -4 or x = 2 ✅

Explanation :

Quadratic formula : ax² + bx + c = 0 where a ≠ 0

The number of real-number solutions (roots) is determined by the discriminant (b² - 4ac) :

If b² - 4ac > 0 , There are 2 real-number solutions

If b² - 4ac = 0 , There is 1 real-number solution.

If b² - 4ac < 0 , There is no real-number solution.

The roots of the equation are determined by the following calculation:

$x = \frac{ - b \pm \sqrt{ {b}^{2} - 4ac } }{2a}$

Here, we have :

a = 1
b = 2
c = -8

1) Calculate the discriminant :

b² - 4ac ⇔ 2² - 4(1)(-8) ⇔ 4 - (-32) ⇔ 36

b² - 4ac = 36 > 0 ; The equation admits two real-number solutions

2) Calculate the roots of the equation:

▪️ (1)

$x_1 = \frac{ - b - \sqrt{ {b}^{2} - 4ac} }{2a} \\ \\ x_1 = \frac{ - 2 - \sqrt{36} }{2(1) } \\ \\ x_1 = \frac{ - 2 - 6}{2} \\ \\ x_1 = \frac{ - 8}{2} \\ \\ \blue{\boxed{\red{x_1 = -4}}}$

▪️ (2)

$x_2 = \frac{ - b + \sqrt{ {b}^{2} - 4ac } }{2a} \\ \\ x_2 = \frac{ - 2 + \sqrt{36} }{2(1)} \\ \\ x_2 = \frac{ - 2 + 6}{2} \\ \\ x_2 = \frac{4}{2} \\ \\ \red{\boxed{\blue{x_2 = 2}}}$

>> Therefore, your answers are x = -4 or x = 2.

Learn more about quadratic equations:

brainly.com/question/27638369

6 0

2 years ago

Read 2 more answers

Suppose you know a certain parabola has a vertex of (2, 1) and a y-intercept of 4. By symmetry, you can conclude that the parabo

kodGreya [7K]

Answer:

Step-by-step explanation:

We are given a parabola with a vertex point of (2, 1) and a y-intercept of y = 4.

And we want to determine another point on the parabola.

Recall that a parabola is symmetric along the axis of symmetry, which is the x-coordinate of the vertex.

Note that since the y-intercept of the parabola is y = 4, this means that a point on our parabola is (0, 4).

To get from (2, 1) to (0, 4), we move two units left and three units up.

Since the parabola is symmetric along axis of symmetry, another point on the parabola will be two units right and three units up. This yields (2 + 2, 1 + 3) or (4, 4).

Our answer is A.

5 0

3 years ago

Circle O has a circumference of 36π cm.

ehidna [41]

Answer:

r = 18 cm

Step-by-step explanation:

The formula for the circumference of a circle is 2πr.

Hence,

2πr = 36π

r = 18 cm

3 0

2 years ago