Hi,
Concept: The given problem is based on 3 Dimensional Geometry.
Consider three axes in defined space be x, y & z in their positive directions then - x , -y & -z be their negative axes.
The coordinate of given point A(x1, y1, z1) = (1, -3, 4)
If we take the reflection of point A about xz - plane x and z coordinates will remain same and y-coordinate will give its reflection. It means the value of y-coordinate will be changed which will be +ve 3.
Hence, the reflection of A(1, -3, 4) will be A'(x2, y2,z2= (1, 3, 4).
Answer: PEMDAS
8•2 = 16
16+3x = -7
-3 -3
16 + x = -10
-16 -16
X= -26
Step-by-step explanation:
Use the formula i = p*r*t:
$456
$456 = $1600*r*6. Solving for r, r = ----------------- = 0.0475, or 4 3/4%
($1600)(6)
Answer:
Step-by-step explanation:
Move −2.
3x+5y−2
just divide 20 by coefficient of x
x < 20/2
x < 10
