What is the approximate energy of a photon having a frequency of 4 x 10^7 Hz? (h = 6.6 x 10^-34 J . s)
1 answer:
Answer:
2.64 × J
Explanation:
I think you should mark it a physics question instead but anyway.
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The Planck equation should be applied:
E = hv , while E is energy of proton; h is Planck constant; and v is frequency.
E = 6.6 × × 4 ×
= 6.6 × 4 ×
= 2.64 × J
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