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3 years ago

What is the approximate energy of a photon having a frequency of 4 x 10^7 Hz? (h = 6.6 x 10^-34 J . s)

Chemistry

1 answer:

BigorU [14]3 years ago

3 0

Answer:

2.64 × $10^{-26}$ J

Explanation:

I think you should mark it a physics question instead but anyway.

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The Planck equation should be applied:

E = hv , while E is energy of proton; h is Planck constant; and v is frequency.

E = 6.6 × $10^{-34}$ × 4 × $10^{7}$

= 6.6 × 4 × $10^{-27}$

= 2.64 × $10^{-26}$ J

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Answer:

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Explanation:

Identify the reaction:

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Identify the limiting reactant, previously determine the mol of each reactant

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