Question

What is the approximate energy of a photon having a frequency of 4 x 10^7 Hz? (h = 6.6 x 10^-34 J . s)

Answer 1

Answer:

2.64 ×$10^{-26}$ J

Explanation:

I think you should mark it a physics question instead but anyway.

---------------------------------------------------------------------------

The Planck equation should be applied:

E = hv , while E is energy of proton; h is Planck constant; and v is frequency.

E = 6.6 × $10^{-34}$ × 4 × $10^{7}$

  = 6.6 × 4 × $10^{-27}$

  = 2.64 ×$10^{-26}$ J