Can someone help me with this i don't understand it.

The results of the gold foil experiment led to the conclusion that an atom is

viva [34]

$\sf\large \blue{\underbrace{\red{Answer⋆}}}:$

The nucleus of an atom of the element is positively charged and atom has a hollow space inside it.

Explanation:

This experiment was conducted by Rutherford in this experiment. He placed a gold foil and surround it with a screen.

And He exposed gold foil in alpha particles rays in which he noticed that most rays passed through atom which conclude that atom has a large space, some rays get deflected and some reverse their path this show that the positive charge of nucleus of an atom.

4 0

2 years ago

Which of the following is a part of the Kinetic Molecular

GarryVolchara [31]

The Kinetic Molecular Theory exposes, qualitatively and quantitatively, all the laws that the gas field occupies, which explains that molecules in a gas move rapidly.

The Kinetic Molecular Theory describes the behavior of a gas mass, starting from the behavior of the individual molecules.

It proposes that the molecules of a gas are in a rapid continuous random movement, which is only altered by the collisions that take place with each other or with the walls of the container.

All the collisions produced are elastic, that is, the kinetic energy is not modified or altered by said collision.

Therefore, we can conclude that the Kinetic Molecular Theory describes the behavior of gases, and proposes that gas molecules are in constant chaotic motion, colliding elastically with each other rapidly.

Learn more about Kinetic Molecular Theory here: brainly.com/question/8369832

5 0

2 years ago

If you hit the surface of Iron with a photon of energy and find that the ejected electron has a wavelength of .75 nm, what is th

lubasha [3.4K]

Answer:

The wavelength of the incoming photon is 172.8 nm

Explanation:

The wavelength of the incoming photon can be calculated with the photoelectric equation:

$KE = h\frac{c}{\lambda_{p}} - \phi$ (1)

Where:

KE: is the kinetic energy of the electron

h: is Planck's constant = 6.62x10⁻³⁴ J.s

c: is the speed of light = 3.00x10⁸ m/s

$\lambda_{p}$ : is the wavelength of the photon =?

Φ: is the work function of the surface (Iron) = 4.5 eV

The kinetic energy of the electron is given by:

$KE = \frac{p^{2}}{2m} = \frac{(\frac{h}{\lambda_{e}})^{2}}{2m}$ (2)

Where:

p: is the linear momentum = h/λ

m: is the electron's mass = 9.1x10⁻³¹ kg

$\lambda_{e}$ : is the wavelength of the electron = 0.75 nm = 0.75x10⁻⁹ m

Hence, the wavelength of the photon is:

$\frac{(\frac{h}{\lambda_{e}})^{2}}{2m} = h\frac{c}{\lambda_{p}} - \phi$

$\lambda_{p} = \frac{hc}{\frac{h^{2}}{2m\lambda_{e}^{2}} + \phi} = \frac{6.62 \cdot 10^{-34} J.s*3.00\cdot 10^{8} m/s}{\frac{(6.62 \cdot 10^{-34} J.s)^{2}}{2*9.1 \cdot 10^{-31} kg*(0.75 \cdot 10^{-9} m)^{2}} + 4.5 eV*\frac{1.602 \cdot 10^{-19} J}{1 eV}} = 1.728 \cdot 10^{-7} m = 172.8 nm$