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Juli2301 [7.4K]
3 years ago
10

Study the animal in the image below. What can you infer about the animal from this image?

Chemistry
1 answer:
zaharov [31]3 years ago
3 0
D, hope you do well.
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Your lab partner named this compound 3-methyl-4-n-propylhexane, but that is not correct.
loris [4]

<u>Answer:</u> The correct IUPAC name of the alkane is 4-ethyl-3-methylheptane

<u>Explanation:</u>

The IUPAC nomenclature of alkanes are given as follows:

  • Select the longest possible carbon chain.
  • For the number of carbon atom, we add prefix as 'meth' for 1, 'eth' for 2, 'prop' for 3, 'but' for 4, 'pent' for 5, 'hex' for 6, 'sept' for 7, 'oct' for 8, 'nona' for 9 and 'deca' for 10.
  • A suffix '-ane' is added at the end of the name.
  • If two of more similar alkyl groups are present, then the words 'di', 'tri' 'tetra' and so on are used to specify the number of times these alkyl groups appear in the chain.

We are given:

An alkane having chemical name as 3-methyl-4-n-propylhexane. This will not be the correct name of the alkane because the longest possible carbon chain has 7 Carbon atoms, not 6 carbon atoms

The image of the given alkane is shown in the image below.

Hence, the correct IUPAC name of the alkane is 4-ethyl-3-methylheptane

4 0
3 years ago
how many grams of molecular oxygen (O2) is produced from 13.8 grams of calcium chlorate (Ca(ClO3)2)in the following chemical rea
olga2289 [7]

Answer:

6.72 g

Explanation:

Given data:

Mass of calcium chlorate = 13.8 g

Mass of oxygen produced = ?

Solution:

Chemical equation:

Ca(ClO₃)₂        →      CaCl₂ + 3O₂

Number of moles of calcium chlorate:

Number of moles = mass / molar mass

Number of moles = 13.8 g/ 206.98 g/mol

Number of moles = 0.07 mol

Now we will compare the moles of oxygen and  calcium chlorate.

                 Ca(ClO₃)₂         :            O₂

                      1                   :              3

                    0.07               :            3×0.07=0.21 mol

Mass of oxygen:

Mass = number of moles × molar mass

Mass = 0.21 mol × 32 g/mol

Mass = 6.72 g

3 0
3 years ago
In the water cycle, matter moves against the pull of gravity during
V125BC [204]
Evaporation and transpiration
5 0
3 years ago
Read 2 more answers
Determine the number of atoms of each element in the empirical formula of a compound with the following composition:
34kurt
To determine the empirical formula of the compound, we assume a basis of 100 g of this compound. We calculate as follows:

C = 68.75 g
H = 10.90 g
O = 20.35 g

We convert these mass to moles,
C = 68.75 g / 12.01 g/mol = 5.72 mol
H = 10.90 g / 1.01 g/mol = 10.79 mol
O = 20.35 g / 16 g/mol = 1.27 mol

C = 5.72 mol / 1.27 mol = 5
H = 10.79 mol / 1.27 mol = 8
O = 1.27 mol / 1.27 mol = 1

C5H8O
6 0
3 years ago
Read 2 more answers
Compare and contrast the concepts of average mass and relative mass​
Sphinxa [80]

Answer:

Relative and average atomic mass both describe properties of an element related to its different isotopes. However, relative atomic mass is a standardized number that's assumed to be correct under most circumstances, while average atomic mass is only true for a specific sample.

Explanation:

6 0
4 years ago
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