Study the animal in the image below. What can you infer about the animal from this image?

Please help me and explanation would be really awesome thank you!

valentina_108 [34]

Answer:

So the answer would be 10 moles

Explanation:

1) Start with the molecular formula for water: $H_{2} O!$

2) If there are 10 moles of water use a mole ratio to calculate the moles of oxygen it would produce.

(This question is... interesting... since they chose an element that is diatomic in free state so It could TECHNICALLY be two answers, moles of O or moles of $O_{2}$ )

The mole ratio is 1 moles of $H_{2}O$ to 1 moles of O. This is because the coefficient for oxygen in water is simple 1, so the ratio is 1:1.

3) that means if 10 moles of water decompose, they decompose into 10 moles of $H_{2}$ and 10 moles of O.

Extra:

About what I was saying before about the question being slightly interesting:

10 moles of pure oxygen is produced but free state oxygen exists as $O_{2}$ so it could possibly be 10 OR 5! However, notice it says elements. This leads me to believe the answer is 10 (monatomic oxygen) instead of 5 (free state/diatomic oxygen).

I hope this helps!

4 0

2 years ago

What is the definition for floating

creativ13 [48]

Answer:

"1. buoyant or suspended in water or air.

2.not settled in a definite place; fluctuating or variable."

Explanation:

Hope this helps! :)

5 0

3 years ago

Read 2 more answers

What is atomic number of sodium

FromTheMoon [43]

Answer:

Explanation:

Sodium is a chemical element with the symbol Na and atomic number 11. It is a soft, silvery-white, highly reactive metal. Sodium is an alkali metal, being in group 1 of the periodic table. Its only stable isotope is ²³Na. The free metal does not occur in nature, and must be prepared from compounds.

5 0

2 years ago

Read 2 more answers

How many grams of oxygen are required too burn 8.8g of c3h8?

hichkok12 [17]

From the balanced equation:
1mol C3H8 requires 5mol O2 for combustion 
Molar mass C3H8 = 44g/mol 
8.8g C3H8 = 8.8/44 = 0.2mol C3H8 
This will require 5*0.2 = 1.0mol O2 
Molar mass O2 = 32g/mol 
Therefore 32g of O2 required.

4 0

2 years ago

One mole of oxygen gas is at a pressure of 6.00 atm and a temperature of 27.0°C. (a) If the gas is heated at constant volume unt

Umnica [9.8K]

Answer: a) 900 K

b) 1200 K

Explanation:

According to the ideal gas equation:

$PV=nRT$

P = Pressure of the gas = 6.00 atm

V= Volume of the gas = ?

T= Temperature of the gas = 27°C = 300 K $0^00C=273K$

R= Gas constant = 0.0821 atmL/K mol

n= moles of gas = 1

$V=\frac{nRT}{P}=\frac{1\times 0.0821\times 300}{6.00}=4.10L$

a) To calculate the final temperature of the system, we use the equation given by Gay-Lussac Law. This law states that pressure of the gas is directly proportional to the temperature of the gas at constant pressure.

Mathematically,

$\frac{P_1}{T_1}=\frac{P_2}{T_2}$