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Alex17521 [72]
3 years ago
14

The length of the base of a triangle is twice it’s height. If the area of the triangle is 441 square kilometers, find the height

Mathematics
1 answer:
Sonja [21]3 years ago
5 0

Answer:

21 kilometers

Step-by-step explanation:

Let the height be x. Then, the length of the base is 2x. The formula for the area is of the triangle is given by base*height/2. Therefore, the area of the triangle is equal to \frac{x \cdot 2x}{2} = x^2, which is in turn equal to 441. Since x must be positive, then 21^2=441, meaning that the height is 21 kilometers.

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6x - 4

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f(x) + g(x)

= 4x + 8 + 2x - 12 ← collect liketerms

= 6x - 4

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The average monthly mortgage payment including principal and interest is $982 in the united states. if the standard deviation is
Aleonysh [2.5K]
The probability that the monthly payment is more than $1000 will be found as follows;
The payment is normally distributed, thus the z-score will be given by:
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3 years ago
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express answer in exact form. Show all work for full credit. A segment of a circle has a 120 arc and a chord of 8 sq root 3. Fin
Anna35 [415]

Let \alpha be the angle of an arc,  \alpha =120^{\circ}, and r be the radius of the circle.

Then by the cosine rule,

\text{chord}^2=r^2+r^2-2\cdot r\cdot r\cdot \cos \alpha,\\ \\(8\sqrt{3})^2=2r^2-2r^2\cdot \cos 120^{\circ}=2r^2-2r^2\cdot \left(-\dfrac{1}{2}\right)=3r^2,\\ \\192=3r^2,\\ \\r^2=64,\\ \\r=8\ un.

1. Find the area of the sector. Since \alpha =120^{\circ}, then

A_{sector}=\dfrac{\pi r^2}{3}=\dfrac{64\pi}{3}\ un^2.

2. Find the area of the triangle formed by two radii and chord:

A_{triangle}=\dfrac{1}{2}\cdot r\cdot r\cdot \sin \alpha=\dfrac{64}{2}\cdot \dfrac{\sqrt{3}}{2}=16\sqrt{3}\ un^2.

3. The area of the segment is

A_{segment}=A_{sector}-A_{triangle}=\dfrac{64\pi}{3}-16\sqrt{3}=\dfrac{64\pi-48\sqrt{3}}{3}\ un^2.

Answer: \dfrac{64\pi-48\sqrt{3}}{3}\ un^2.

6 0
3 years ago
Can you help me out and simplify?
Angelina_Jolie [31]

Answer:

 = 1/3  * sqrt(1/2)

Step-by-step explanation:

sqrt(1/18)

We know that sqrt(a/b) = sqrt(a)/sqrt(b)

sqrt(1/18)

sqrt(1)/sqrt(18)

1/sqrt(18)

We also know that sqrt(ab) = sqrt(a) sqrt(b)

1/sqrt(18) = 1/ sqrt(9)sqrt(2)

              = 1/(3sqrt(2))

                 = 1/3 * 1/ sqrt(2)

We know that sqrt(a/b) = sqrt(a)/sqrt(b)

               = 1/3  * sqrt(1/2)

5 0
3 years ago
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