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3 years ago

How many variable terms are in the expression 3x3y + 5x2 + y + 9?

1 answer:

7 0

Three variable terms appear in this expression. Although 9xy has two variables, they combine to make one term.

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Convert from general form to standard form x^2 + 4y^2 + 6x-40y+9 =0

Burka [1]

$x^2 + 4y^2 + 6x-40y+9 =0\\x^2 + 6x+9+4y^2-40y=0\\x^2+6x+9+4y^2-40y+100-100=0\\(x+3)^2+(2y-10)^2=100$

P.S. Hello from Russia

7 0

2 years ago

Simplify the following completely, show all work. √-45

scoray [572]

Answer:

$3\sqrt{5}i$

Step-by-step explanation:

$\sqrt{-45}$

$\sqrt{-9*5}$

$\sqrt{-9}\sqrt{5}$

$3i\sqrt{5}$

$3\sqrt{5}i$

7 0

2 years ago

Find the slope of the line that passes through the points (0-2) and (1.4).

vredina [299]

Answer:

m = 6

Step-by-step explanation:

$m=\frac{rise}{run}=\frac{4+2}{1-0}=\frac{6}{1}=\boxed{6}$

Hope this helps!

4 0

2 years ago

Read 2 more answers

Type the correct answer in each box.

Vilka [71]

Answer:

2x + 2y = 24

Step-by-step explanation:

5 0

2 years ago

At the beginning of year 1, Josie invests $400 at an annual compound interest

zvonat [6]

Answer:

The explicit formula that can be used is $A=\$400(1.05)^{2}$

The account's balance at the beginning of year 3 is $A=\$441$

Step-by-step explanation:

we know that

The compound interest formula is equal to

$A=P(1+\frac{r}{n})^{nt}$

where

A is the Final Investment Value

P is the Principal amount of money to be invested

r is the rate of interest in decimal

t is Number of Time Periods

n is the number of times interest is compounded per year

in this problem we have

$t=2\ years\\ P=\$400\\ r=0.05\\n=1$

substitute in the formula above

$A=\$400(1+\frac{0.05}{1})^{1*2}$

$A=\$400(1.05)^{2}$

$A=\$441$

3 0

2 years ago