Question

Please help me with this....and show all the steps correctly...​

Answer 1

Answer:

$12 \frac{m}{s}$

Explanation:

• The time starts when the front of the train first gets on the bridge, and when the back end clears the bridge.
• Thus we are calculating the distance of 600 meters in 50 seconds.

$600m \div 50s = 12 \frac{m}{s}$

Answer 2

$Given, \: Displacement, \: s \: = \: 450m \: + \: 150m \\ = \: 600m \\ Time, \: t \: = \: 50s \\ We \: know \: that, \: Velocity, v \: = \: \frac{Displacement}{Time} \\ = > v = \frac{s}{t} \\ = > v = \frac{600m}{50s} \\ = > v = \frac{12m}{s} \\ = > v = 12m {s}^{ - 1}$

So, the velocity of the train is 12m/s or 12ms^(-1).