You are correct. For each of the three possibilities for their second day, there are two possibilities for the third day.
The total number of possibilities is 3*2 = 6.
Answer:
value of x = 26
value of y = 26 \|2
( 26 root 2 )
Step-by-step explanation:
here's the solution : -
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![\sin(45) = \frac{perpendicular}{hypotenuse}](https://tex.z-dn.net/?f=%20%5Csin%2845%29%20%20%3D%20%20%20%5Cfrac%7Bperpendicular%7D%7Bhypotenuse%7D%20)
=》
![\frac{1}{ \sqrt{2} } = \frac{26}{y}](https://tex.z-dn.net/?f=%20%5Cfrac%7B1%7D%7B%20%5Csqrt%7B2%7D%20%7D%20%20%3D%20%20%5Cfrac%7B26%7D%7By%7D%20)
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![y = 26 \sqrt{2}](https://tex.z-dn.net/?f=y%20%3D%2026%20%5Csqrt%7B2%7D%20)
and
![\tan(45) = \frac{perpendicular}{base}](https://tex.z-dn.net/?f=%20%5Ctan%2845%29%20%20%3D%20%20%5Cfrac%7Bperpendicular%7D%7Bbase%7D%20)
=》
![1 = \frac{26}{x}](https://tex.z-dn.net/?f=1%20%3D%20%20%5Cfrac%7B26%7D%7Bx%7D%20)
=》
![x = 26](https://tex.z-dn.net/?f=x%20%3D%2026)
Answer:
Step-by-step explanation:
Answer:
One- half
Step-by-step explanation:
Since the density is uniform
Mass of the sphere = [(4/3) π r^3] d
where d is the uniform density.
Mass of the sphere = [(4/3) π d] r^3 = k r^3
where k = [(4/3) π d] is a constant
Weight = mg = G m M / r^2 = G m [k r^3] /r^2 = G m k r
Using Gauss’ law for gravitation,
Half way to the center of a planet the weight is only due to the inner sphere and the outer sphere does not contribute to his weight,
Inside his weight is mg’ = (G m k r) /2 = mg/2
Answer is one-half.