Answer:
We need a sample size of 564.
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of 
, and a confidence level of 
, we have the following confidence interval of proportions.
In which
z is the zscore that has a pvalue of 
.
For this problem, we have that:
The margin of error is:
95% confidence level
So 
, z is the value of Z that has a pvalue of 
, so 
.
Based upon a 95% confidence interval with a desired margin of error of .04, determine a sample size for restaurants that earn less than $50,000 last year.
We need a sample size of n
n is found when 
So
Rounding up
We need a sample size of 564.
First off, add 3 to both sides of the equation.
6n - 3 + 3 > -18 + 3
Then, your equation should look like this: 6n > -15
Next, divide both sides by 6.
6n/6 > -15/6
Your answer is n > -5/2
Answer:
the ratio of 5 to 15 is
1/3 hope i helped please check out my latest question i need help with homework
Step-by-step explanation:
its simplified
Answer:
16%
Step-by-step explanation:
The additional wage amount is $80.
The original wage amount is $500.
The ratio of the two is ...
$80/$500 = 0.16 = 16/100
To express that ratio as a percentage, multiply it by 100%.
0.16 × 100% = 16%
_____
It might help you to think of the percent sign (%) as a fancy way to write "per hundred" (/100). Of course, using your knowledge of place value, you know that 0.16 = sixteen hundredths = 16/100.
Realizing the meaning of the % sign, you can immediately write this as 16%.
Answer:
In a decimal it would be 177.577
In a fraction it would be 177 577/1000
