The protons are equivalent to the atomic number, so we can determine that the element being expressed here is Magnesium. If you are ever stuck on what element you are finding your information from, just remember that the number of protons is the exact same as the atomic number in ANY situation :)
The charge of magensium is +2, with an atomic mass of 24. So A would be your answer :)
The object that I think has potential energy within the images posted is the skateboard at the top of the ramp.
<h3>Why do i think this one has potential energy?</h3>
Potential energy is a type of mechanical energy in which there is a type of stored energy that can be transformed into another type of energy. This energy is given by the <u>location of the body</u> with respect to a force field.
I selected the image of the skateboard at the top of the ramp since going up there uses kinetic energy and when it is on top of the ramp, waiting to go down, this kinetic energy is stored in potential energy that is ready to be released. The higher the height at which it is launched, <u>the more its potential energy will be</u>.
Therefore, we can confirm that the object that I think has potential energy within the images posted is the skateboard at the top of the ramp.
To learn more about potential energy visit: brainly.com/question/24284560?referrer=searchResults
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Electronic configuration is given by
- 1s orbital is filled
- 2s orbital is unfilled
So
Answer:
9 . this was not able the first one. it has to go on, I will not sure about
Answer:
16.2 J
Explanation:
Step 1: Given data
- Specific heat of liquid bromine (c): 0.226 J/g.K
- Volume of bromine (V): 10.0 mL
- Initial temperature: 25.00 °C
- Final temperature: 27.30 °C
- Density of bromine (ρ): 3.12 g/mL
Step 2: Calculate the mass of bromine
The density is equal to the mass divided by the volume.
ρ = m/V
m = ρ × V
m = 3.12 g/mL × 10.0 mL
m = 31.2 g
Step 3: Calculate the change in the temperature (ΔT)
ΔT = 27.30 °C - 25.00 °C = 2.30 °C
The change in the temperature on the Celsius scale is equal to the change in the temperature on the Kelvin scale. Then, 2.30 °C = 2.30 K.
Step 4: Calculate the heat required (Q) to raise the temperature of the liquid bromine
We will use the following expression.
Q = c × m × ΔT
Q = 0.226 J/g.K × 31.2 g × 2.30 K
Q = 16.2 J
