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3 years ago

To increase a gas ' average kinetic energy must do what?

1 answer:

5 0

The kinetic energy of a gas is a measure of its Kelvin temperature. An increase in temperature increases the speed in which the gas molecules move. All gases at a given temperature have the same average kinetic energy. Lighter gas molecules move faster than heavier molecules.

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What is basicity in acids?

timama [110]

Basicity of an acid is the number of hydrogen ions which can be produced by one molecule of an acid

6 0

3 years ago

A large cyclotron directs a beam of He++ nuclei onto a target with a beam current of 0.250 mA. (a) How many He++ nuclei per seco

nikitadnepr [17]

Answer:

a. 7.8*10¹⁴ He⁺⁺ nuclei/s

b. 4000s

c. 7.7*10⁸s

Explanation:

I = 0.250mA = 2.5 * 10⁻³A

Q = 1.0C

1 e- contains 1.60 * 10⁻¹⁹C

But He⁺⁺ Carrie's 2 charge = 2 * 1.60*10⁻¹⁹C = 3.20*10⁻¹⁹C

(A).

No. Of charge per second = current passing through / charge

1 He⁺⁺ = 2.50 * 10⁻⁴ / 3.2*10⁻¹⁹C

1 He⁺⁺ = 7.8 * 10¹⁴ He⁺⁺ nuclei

(B).

I = Q / t

From this equation, we can determine the time it takes to transfer 1.0C

I = 1.0 / 2.5*10⁻⁴ = 4000s

(C).

Time it takes for 1 mol of He⁺⁺ to strike the target =?

Using Avogadro's ratio,

1.0 mole of He = (6.02 * 10²³ ions/mol ) * (1 / 7.81*10¹⁴ He ions)

Note : ions cancel out leaving the value of the answer in mols.

1.0 mol of He = 7.7 * 10⁸s

8 0

3 years ago

What is the formula for the aqueous salt produced when hydroiodic acid is neutralized by potassium hydroxide?

coldgirl [10]

Answer:

KOH(aq) + HCI(aq) -----> KCI(aq )+ H2O

base acid salt water

hope this helps :)

Explanation:

5 0

3 years ago

What will be the bond angles for an sp3d2 hybridized atom participating in six identical single covalent bonds

Romashka [77]

Answer: electrons

Explanation:

5 0

2 years ago

Gaseous butane will react with gaseous oxygen to produce gaseous carbon dioxide and gaseous water . Suppose 1.74 g of butane is

xeze [42]

Answer : The mass of $CO_2$ produced will be, 5.3 grams.

Explanation : Given,

Mass of $C_4H_{10}$ = 1.74 g

Mass of $O_2$ = 11 g

Molar mass of $C_4H_{10}$ = 58 g/mole

Molar mass of $O_2$ = 32 g/mole

Molar mass of $CO_2$ = 44 g/mole

First we have to calculate the moles of $C_4H_{10}$ and $O_2$ .

$\text{Moles of }C_4H_{10}=\frac{\text{Mass of }C_4H_{10}}{\text{Molar mass of }C_4H_{10}}=\frac{1.74g}{58g/mole}=0.03moles$

$\text{Moles of }O_2=\frac{\text{Mass of }O_2}{\text{Molar mass of }O_2}=\frac{11g}{32g/mole}=0.34moles$

Now we have to calculate the limiting and excess reagent.

The balanced chemical reaction is,

$2C_4H_{10}+13O_2\rightarrow 8CO_2+10H_2O$

From the balanced reaction we conclude that

As, 2 moles of $C_4H_{10}$ react with 13 mole of $O_2$

So, 0.03 moles of $C_4H_{10}$ react with $\frac{13}{2}\times 0.03=0.195$ moles of $O_2$

From this we conclude that, $O_2$ is an excess reagent because the given moles are greater than the required moles and $C_4H_{10}$ is a limiting reagent and it limits the formation of product.

Now we have to calculate the moles of $CO_2$ .

As, 2 moles of $C_4H_{10}$ react to give 8 moles of $CO_2$

So, 0.03 moles of $C_4H_{10}$ react to give $\frac{8}{2}\times 0.03=0.12$ moles of $CO_2$

Now we have to calculate the mass of $CO_2$ .

$\text{Mass of }CO_2=\text{Moles of }CO_2\times \text{Molar mass of }CO_2$

$\text{Mass of }CO_2=(0.12mole)\times (44g/mole)=5.3g$

Therefore, the mass of $CO_2$ produced will be, 5.3 grams.

5 0

3 years ago