Answer:
4.90 moles of 
will produce (9.8) moles of 
,
(4.90) moles of 
and
(39.2) moles of 
Explanation:
From the question we are told that
The number of moles of is 
The formation reaction of is
From the reaction we see that
1 mole of is formed by 2 moles of 1 mole of and 4
This implies that
4.90 moles of will produce (2 * 4.90) moles of ,
(1 * 4.90) moles of and
(8 * 4.90) moles of
So
4.90 moles of will produce (9.8) moles of ,
(4.90) moles of and
(39.2) moles of
Hydrochloric Acid would best be described as an Arrhenius and BrØnsted-Lowrey acid.
<h3>
Is Hydrochloric Acid considered a
Brønsted-Lowry acid?</h3>
Hydrochloric Acid HCl(g) is the proton donor and therefore a Brønsted-Lowry acid.
<h3>
Is Hydrochloric Acid considered an Arrhenius
acid?</h3>
According to Arrhenius theory, hydrochloric acid is an acid which gives hydrogen ions in water but according to Bronsted-Lowry theory, hydrochloric acid is an acid because it donates a proton to the water molecule.
<h3>Is
Hydrochloric Acid considered a Lewis acid?</h3>
Hydrochloric acid (HCl) cannot be classified as a Lewis acid since it cannot accept an electron pair.
Thus, hydrochloric Acid would best be described as an Arrhenius and BrØnsted-Lowrey acid.
Learn more about Hydrochloric Acid here: brainly.com/question/3229358
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Answer:
Kp is 0.00177
Explanation:
We state the equilibrium:
CO(g) + Cl₂(g) ⇆ COCl₂(g)
Initially we have these partial pressures
1.86 atm for CO and 1.27 for chlorine.
During the reaction, x pressure has been converted. As we have 0.823 atm as final pressure in the equilibrium for COCl₂, pressure at equilibrium for CO and chlorine will be:
1.86 - x for CO and 1.27 - x for Cl₂.
And x is the pressure generated for the product, because initially we don't have anything from it. So pressure in equilibrium for the reactants will be:
1.86 - 0.823 = 1.037 atm for CO
1.27 - 0.823 = 0.447 atm for Cl₂
Let's make, expression for Kp:
Partial pressure in eq. for COCl₂ / P. pressure in eq. for CO . P pressure in eq. for Cl₂
Kp = 0.823 / (1.037 . 0.447) → 0.00177
Temp change = Q/(mass x sph)
Temp change =57/(22 x .903)
Temp Change = 2.97 ∘C
Temp change 3.0 ∘C
