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netineya [11]
4 years ago
9

How many moles are in 12 gr of magnesium?

Chemistry
1 answer:
myrzilka [38]4 years ago
5 0

Answer: 0.5 mole Mg

Explanation: solution:

12 g Mg x 1 mole Mg / 24 g Mg

= 0.5 mole Mg

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Answer: F. Endothermic…………………
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What is one benfit of using ph instead of molar concentrations?
puteri [66]

One benefit of using ph instead of molar concentrations is that since molarity is a rate of “ moles per liter" ,  Molarity (M) is used to measure the concentration of hydrogen ions in a solution, which is used with pH applications. ... The H+ is the molarity number, which shows the concentration of hydrogen ions in the solution.

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3 years ago
18. The mass of a quantity of NiCl2 is 24.6 g. How many formula units are in the sample?
Charra [1.4K]

Answer is: A. 1.1 3 1023 NiCl2 formula units.

m(NiCl₂) = 24.6 g; mass of nickel(II) chloride.

M(NiCl₂) = 129.6 g/mol; molar mass of nickel(II) chloride.

n(NiCl₂) = m(NiCl₂) ÷ M(NiCl₂).

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N(NiCl₂) = n(NiCl₂) · Na.

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N(NiCl₂) = 1.13·10²³; number of formula units.

4 0
3 years ago
Read 2 more answers
Calculate Ecell at 80 ºC for a voltaic cell based on the following redox reaction: H2(g, 1.25 atm) + 2AgCl(s) → 2Ag(s) + 2H+(aq,
iris [78.8K]

Answer:

Ecell = +0.25V

Explanation:

the half-cell reactions for a voltanic cell

cathode(reduction): 2H⁺(aq) + 2e⁻ ------- H₂(g)

anode(oxidation): 2AgCl(s) ------- 2Ag⁺(aq) + 2Cl⁻ + 2e⁻

we have the standard cell potential E⁺cell = 0.18V at 80C respectively

Q = [H⁺]/[Cl⁻]

sub for [H+] = 0.10M and [Cl-] = 1.5M

Q= 0.1M/1.5M

Q = 0.067

Ecell = E⁺cell - \frac{0.059}{n} logQ

= 0.18 - \frac{0.056}{1} log 0.067

0.18- 0.059(-1.174)

Ecell = +0.25V

6 0
3 years ago
When the procedure calls for making a more dilute solution of an acid, or mixing an acid with other solutions, what is the corre
Fed [463]

Answer:

The correct order it b. always add acid last.

Explanation:

Adding acid first could result on a violent reaction and heat or fumes can be generated. The best approach is to always add all the water or non-acid component first, or add a significant portion before adding the acid slowly to the mixture.

7 0
3 years ago
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