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3 years ago

I need help on how to do this. Please help

Mathematics

1 answer:

Sveta_85 [38]3 years ago

8 0

Hi there! I can help you! To solve this question, we can write and solve a proportion. Candida ran 100 yards in 12.7 seconds and the timekeeper ran 100 yards in 11.4 seconds. Let's start with Candida. We could solve this by setting up the proportion to make it look like this: 100/12.7 = 220/x. You do this, because we're looking for the amount of time it would take for Candida to run 220 yards. Le'ts cross multiply the values. When you do that, you get 2,794 = 100x. Now, divide each side by 100 to isolate the "x". When you do, you get x = 27.94. x = 27.94. We found Candida's time. Now, let's look for the other person's time. Set up a proportion again. 100/11.4 = 220/x. We are looking for the other person's time. Repeat the steps. Cross multiply the values in order to get 2,508 = 100x. Now, divide each side by 100 to isolate the "x". When you do, you get 25.08. x = 25.08. We found the other person's time. Here are the answers easier to read.

Amount of time to run 220 yards

Candida: 27.94 seconds
Other person's time: 25.08 seconds

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Step-by-step explanation:

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Here we need to solve:

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Notice that the two values:

y = 3

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We can simplify the right side to get:

$\frac{2}{y - 3} + \frac{6}{y + 3 } = \frac{\frac{2}{y-3}}{\frac{6}{y + 3} } = \frac{2*(y + 3)}{6*(y - 3)} = 3*\frac{y + 3}{y - 3}$

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Now we can multiply both sides by (y + 3)

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$2*(y + 3) + 6*(y - 3) = 3*(y + 3)*(y + 3)\\\\2*y + 6 + 6*y - 18 = 3*(y^2 + 2*y*3 + 9)\\\\8*y - 12 = 3*y^2 + 6*y + 33\\\\0 = 3*y^2 + 6*y + 33 - 8*y + 12\\\\0 = 3*y^2 - 2*y + 45$

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