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Oksi-84 [34.3K]
3 years ago
5

PLEASE HELP VERY CONFUESED

Mathematics
2 answers:
Eva8 [605]3 years ago
7 0
V=(4/3)pir^3
r=3
V=(4/3)pi3^3
V=36pi
v=113.04 cubic feet
IgorC [24]3 years ago
3 0
The answer is 113.40 ft^3 I hope that i help you ????
have a great day!!!
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Consider the following equations and name the property of equality used to solve for the variable.
Viktor [21]

9514 1404 393

Answer:

  A. subtraction

  B. division

  C. multiplication

  D. addition

Step-by-step explanation:

Observe what is done to the variable. Choose the operation that turns the unwanted value into the appropriate identity element.

A. 3.75 is added. To make that value be 0, we subtract 3.75.

B. -3 is multiplied. To make that value be 1, we divide by -3.

C. m is divided by 5. To make that 1/5 multiplier be 1, we multiply by 5.

D. 4 is subtracted. To make that value be zero, we add 4.

_____

<em>Additional comment</em>

Since subtraction is the same as addition of the opposite, and division is the same as multiplication by the reciprocal, the only two properties we really need are the <em>addition property</em> and <em>multiplication property</em>. Your grader may disagree.

5 0
3 years ago
Please Help I Will Mark Brainly!!
Nata [24]

C.

he starts 6500 ft up do that's the b in y=mx+b.

the m is -250 because that's the rate, and it's negative because he's going down.

4 0
3 years ago
What is <br>the answer. ​
lesantik [10]
Positive 28 because to negative will equal a positive number
7 0
2 years ago
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Is the number 3 a rational number?
VikaD [51]

Answer:

Yes.

Step-by-step explanation:

The number 3 is a <u>natural number</u>, and all of these types of numbers are rational.

Another way to look at it is if a number can be <u>written as a fraction</u>, the number is rational.

5 0
3 years ago
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David found and factored out the GCF of the polynomial 80b4 – 32b2c3 + 48b4c. His work is below. GFC of 80, 32, and 48: 16 GCF o
BlackZzzverrR [31]

Answer: The correct statements are

The GCF of the coefficients is correct.

The variable c is not common to all terms, so a power of c should not have been factored out.

David applied the distributive property.

Step-by-step explanation:

GCF = Greatest common factor

1) GCF of coefficients : (80,32,48)

80 = 2 × 2 × 2 × 2 × 5

32 = 2 × 2 × 2 × 2 × 2

48 = 2 × 2 × 2 × 2 × 3

GCF of coefficients : (80,32,48) is 16.

2) GCF of variables :(b^4,b^2,b^4)

b^4= b × b × b × b

b^2 = b × b

b^4 =b × b × b × b

GCF of variables :(b^4,b^2,b^4) is b^2

3) GCF of c^3 and c: c is not the GCF of the polynomial. The variable c is not common to all terms, so a power of c should not have been factored out.

4) 80b^4-32b^2c^3+48b^4c

=16b^2(5b^2-2c^3+3b^2c)

David applied the distributive property.

7 0
3 years ago
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