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IrinaVladis [17]
3 years ago
6

A right angled triangular prism has length 3m, breadth 2m and height 2.5m. If the mass of the prism is 3.4kg, find its density​

Mathematics
1 answer:
ioda3 years ago
4 0

Answer:

The density of the prism is 0.453 kilograms per cubic meter.

Step-by-step explanation:

Let suppose that mass in the prism is uniformly distributed. Then, the definition of density (\rho), in kilograms per cubic meter, is defined by the equation below:

\rho = \frac{m}{V} (1)

Where:

m - Mass, in kilograms.

V - Volume of the right angle triangle prism, in cubic meters.

Besides, the volume of the right angle triangle prism is:

V = \frac{1}{2}\cdot b\cdot h\cdot l (2)

Where:

b - Breadth of the base, in meters.

h - Height of the base, in meters.

l - Length of the base, in meters.

If we know that b = 2\,m, h = 2.5\,m, l = 3\,m and m = 3.4\,kg, then the density of the prism is:

V = 7.5\,m^{3}

\rho = 0.453\,\frac{kg}{m^{3}}

The density of the prism is 0.453 kilograms per cubic meter.

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Answer:

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Step-by-step explanation:

Given the function

f\left(x\right)=x^3-6x^2+3x+10

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solving to get the zeros

f\left(x\right)=x^3-6x^2+3x+10

0=x^3-6x^2+3x+10              ∵  f(x)=0

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Using the zero factor principle

if  ab=0\:\mathrm{then}\:a=0\:\mathrm{or}\:b=0\:\left(\mathrm{or\:both}\:a=0\:\mathrm{and}\:b=0\right)

x+1=0\quad \mathrm{or}\quad \:x-2=0\quad \mathrm{or}\quad \:x-5=0

x=-1,\:x=2,\:x=5

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x=-1,\:x=2,\:x=5

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