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4 years ago

Simplify square root of 2 over cube root of 2.

Mathematics

1 answer:

DochEvi [55]4 years ago

8 0

The anwser is A. 2 to the power of 1 over 6

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Find the area of the triangle A) B) 09 11 ft2 D) 224²

Romashka-Z-Leto [24]

Answer:

Step-by-step explanation:

Area of a triangle = $\frac{bh}{2}$

where b = base length and h = height

the triangle shown has a base length of 2 and 1/2 and a height 4. and 2/5

So area =

$\frac{2\frac{1}{2} *4\frac{2}{5} }{2} \\\\2\frac{1}{2} *4\frac{2}{5} =11\\\\\frac{11}{2} =5.5$

5.5 also = $5\frac{1}{2}$

Hence, the correct answer is A

7 0

3 years ago

A money market fund advertises a simple interest rate of 88%. Find the total amount received on an investment of $4000 for 15

Anna007 [38]

$\bf \qquad \textit{Simple Interest Earned}\\\\
I = Prt\qquad 
\begin{cases}
I=\textit{interest earned}\\
P=\textit{original amount deposited}\to& \$4000\\
r=rate\to 88\%\to \frac{88}{100}\to &0.88\\
t=years\to \frac{15}{12}\to &\frac{5}{4}
\end{cases}
\\\\\\
I=4000\cdot 0.88\cdot \cfrac{5}{4}$

6 0

4 years ago

Show your work 2) Is(-3,-7) a solution to 4x – 8y < 24 Show your work

asambeis [7]

Answer: false, 44 is not less than 24

Step-by-step explanation:

Substitute-3 for x and -7 for y.

4(-3)-8(-7)<24

-12+56<24

44<24

3 0

4 years ago

Rationalize the denominator of 1 /√3

seropon [69]

$\huge\sf\underline{\purple{❥}\pink{Q}\orange{U}\blue{E}\red{S}\green{T}\purple{I}\pink{O}\red{N}}$

rationalize the denominator of 1/√3

$\huge\sf\underline{\purple{❥}\pink{A}\orange {N}\blue{S}\red{W}\green{E}\purple{R}}$

$\frac{1}{ \sqrt{3} } \\ \\(to \: rationalize \: the \: denominator \\ we \: have \: multiply \: \frac{1}{ \sqrt{3} } \: to \: the \:given \: fraction \: \: \: ) \\ = \frac{1}{ \sqrt{3} } \times \frac{1}{ \sqrt{3} } \\ = ( \frac{1}{ \sqrt{3} } ) {}^{2} \\ = \frac{1}{3}$

HOPE IT HELPS YOU..

7 0

3 years ago

Estimate 5÷10/11 to the nearest whole number

4vir4ik [10]

Answer:

${ \tt{5 \div \frac{10}{11} }} \\ \\ \dashrightarrow \: { \tt{5 \times \frac{11}{10} }} \\ \\ \dashrightarrow \: { \tt{ \frac{55}{10} = 5.5}} \\ \\ \dashrightarrow \: { \boxed{ \tt{ 5 \div \frac{10}{11} \approx \: 6}}}$

3 0

3 years ago

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