Answer
The correct answer is option(C) which is "Index".
Explanation:
Array elements can be differentiated because each element in the array have different index value.In the array all elements are of same data type, so we can not differentiated them on the basis of data type. Also an array can have same value many times, That is why we can not differentiated them on this basis. In the array elements are from any range, so its not possible to distinguish them on range. We can only distinguish elements of an array on their index value because each element have different index in the array.
A only is correct.
Constant-velocity joints are able to transfer torque with zero angular velocity variation and near-zero vibration to the drive wheels at a constant rotational speed, while still accommodating the up-and-down movement of the suspension. In most cases, they are used in front wheel drive vehicles.
Answer and Explanation:
For JAVA programming.
for(int i = 50; i <= 100 i++;)
{
int cubedNum = Math.pow(i, 4);
System.out.println(cubedNum);
}
Answer:
i think its number 4, because its only the tire itself
Explanation:
Answer:
% here x and y is given which we can take as
x = 2:2:10;
y = 2:2:10;
% creating a matrix of the points
point_matrix = [x;y];
% center point of rotation which is 2,2 here
x_center_pt = x(2);
y_center_pt = y(2);
% creating a matrix of the center point
center_matrix = repmat([x_center_pt; y_center_pt], 1, length(x));
% rotation matrix with rotation degree which is 45 degree
rot_degree = pi/4;
Rotate_matrix = [cos(rot_degree) -sin(rot_degree); sin(rot_degree) cos(rot_degree)];
% shifting points for the center of rotation to be at the origin
new_matrix = point_matrix - center_matrix;
% appling rotation
new_matrix1 = Rotate_matrix*new_matrix;
Explanation:
We start the program by taking vector of the point given to us and create a matrix by adding a scaler to each units with repmat at te center point which is (2,2). Then we find the rotation matrix by taking the roatational degree which is 45 given to us. After that we shift the points to the origin and then apply rotation ans store it in a new matrix called new_matrix1.
