Rotation of the Earth contributes to the idea of the Sun setting and rising. The orbit of the Earth around the Sun results in the changing of seasons.
Answer:
v₀ = 677.94 m / s
, θ = 286º
Explanation:
We can solve this exercise using the kinematic expressions, let's work on each axis separately.
X axis
has a relation of aₓ = 5.10 m / s², the motor is on for a time of t = 675 s, reaching the speed vₓ = 3630 m / s, let's use the relation
vₓ = v₀ₓ + aₓ t
v₀ₓ = vₓ - aₓ t
let's calculate
v₀ₓ = 3630 - 5.10 675
v₀ₓ = 187.5 m / s
Y Axis
= v_{oy} - a_{y} t
v_{oy} = v_{y} - a_{y} t
let's calculate
v_{oy} = 4276 - 7.30 675
v_{oy} = -651.5 m / s
we can give the speed starts in two ways
a) v₀ = (187.5 i ^ - 651.5 j ^) m / s
b) in the form of module and angle
Let's use the Pythagorean theorem
v₀ =
v₀ =
v₀ = 677.94 m / s
we use trigonometry
tan θ =
θ = tan⁻¹ \frac{v_{oy} }{v_{ox} }
θ = tan⁻¹ ()
θ = -73.94º
This angle measured from the positive side of the x-axis is
θ‘ = 360 - 73.94
θ = 286º
Answer:
v = 3.135 m/s
Explanation:
given,
mass of car = 2.1 x 10³ Kg
length of driveway = 5.1 m
angle on inclination, θ = 17°
frictional force, f = 4.0 ✕ 10³ N
The force from the newton's second law
The speed of the car
v = 3.135 m/s
Speed of the car at the bottom of the driveway, v = 3.135 m/s
Answer:
The value is
Explanation:
From the question we are told that
The radius of the cylinder is
The charge density of the plasma is
Generally the difference in potential energy of the Tritium ion before entering the cylinder and at the axis of the cylinder is mathematically represented as
Here
is the permitivity of free space with value
So
Generally from energy conservation we have that
Given that the velocity at the axis of the cylinder should be zero then
it means that the kinetic energy at this axis will also be zero
So
Here KE_i is the initial kinetic energy of the Tritium ion which is mathematically represented as
So
=>
=>
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Here m is the mass of Tritium ion which is given in the question
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