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3 years ago

The Zika Virus is most dangerous to which group of people?

Physics

1 answer:

laiz [17]3 years ago

4 0

Answer:

option D pregnant women

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The electric force is exerted by a 40-nC charged particle located at the origin of a Cartesian coordinate system on a 10-nC char

notsponge [240]

Answer:

450 × 10 ⁻⁹ N

Explanation:

From the given:

The direction of force is;

$tan \ \theta = \dfrac{2}{2}$

$\theta =tan ^{-1} (1)$

$\theta = 45^0$

Hence, the angle is 45° counterclockwise from + x-axis

However;

the magnitude of the force is:

$F = \dfrac{kq_1q_2}{r^2}$

$F = \dfrac{(9*10^9 \ Nm^2/C^2 )*( 40 * 10^{-9} \ C ) * (10*10^{-9} \ C)}{(\sqrt{8})^2}$

$F = 450 \times 10^{-9} \ N$

5 0

2 years ago

A defibrillator passes 14.0 A of current through the torso of a person for 0.0300 s. How much charge moves in coulombs?

krek1111 [17]

<h2>Answer:</h2>

4.2 C

<h2>Explanation:</h2>

The charge (Q) moving is the product of the current(I) flowing through the torso of the person and the time taken (t) for the flow.

i.e

Q = I x t

Where;

I = current = 14.0A

t = time taken = 0.0300s

Substituting the values of I and t into the equation above gives

Q = 14.0 x 0.0300

Q = 4.2 C

Therefore quantity of charge moving is 4.2 C

4 0

2 years ago

complete the following equation that represents the complete combustion of hexane in a car engine.C6H14 + O2

mina [271]

The balanced combustion reaction for butane is;

2C4H10 + 13O2 → 8CO2 + 10H2O

Molar mass of water = 18.02 g/mol

Molar mass of oxygen = 32 g/mol

2.46g H2O(1 mol H2O/18.02g)(13 mol O2/10 mol H2O)(32g O2/1 mol O2) = 5.68g O2

5 0

3 years ago

All animals need oxygen. We get oxygen from the air we breathe. How do fish get theirs?

Finger [1]

Um, I not positive, but I think fish don't need oxygen.

6 0

2 years ago

Read 2 more answers

A 40-kg rock is dropped from an elevation of 10 m. What is the velocity of the rock when it is 5-m from the ground?

ivolga24 [154]

Answer:

Explanation:

Given

mass of rock $m=40\ kg$

Elevation of Rock $h=10\ m$

Distance traveled by rock with time

$h=ut+\frac{1}{2}at^2$

where, u=initial velocity

t=time

a=acceleration

here initial velocity is zero

when rock is 5 m from ground then it has traveled a distance of 5 m from top because total height is 10 m

$5=0\times t+\frac{1}{2}(9.8)(t^2)$

$t^2=\frac{10}{9.8}$

$t=1.004\approx 1\ s$

velocity at this time

$v=u+at$

$v=0+9.8\times 1.004$

$v=9.83\ m/s$

6 0

3 years ago