Question

a block of mass 5kg slides down an inclined plane that has an angle of 10 degrees if the inclined plane has no friction and the block starts at a height of 0.8m how much kinetic energy does the block have when it reaches the bottom? acceleration due to gravity is 9.8m/s2. someone help me how to solve this, physics conservation of energy

Answer 1

In this case, the inclined plane is frictionless and therefore energy is perfectly conserved with no losses. The block originally starts off with some gravitational potential energy, which is then completely converted into kinetic energy. So the initial gravitational potential energy is equal to the final kinetic energy.

$PE_{initial} = KE_{final}$
$PE_{initial} =mgh=(5kg)(9.8m/ s^{2} )(0.8m)=39.2 joules$
$KE_{final}=39.2joules$

Answer 2

Answer:

39.2J

Explanation: