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Thepotemich [5.8K]
3 years ago
6

a block of mass 5kg slides down an inclined plane that has an angle of 10 degrees if the inclined plane has no friction and the

block starts at a height of 0.8m how much kinetic energy does the block have when it reaches the bottom? acceleration due to gravity is 9.8m/s2. someone help me how to solve this, physics conservation of energy
Physics
2 answers:
Degger [83]3 years ago
7 0
In this case, the inclined plane is frictionless and therefore energy is perfectly conserved with no losses. The block originally starts off with some gravitational potential energy, which is then completely converted into kinetic energy. So the initial gravitational potential energy is equal to the final kinetic energy.

PE_{initial} =  KE_{final}
PE_{initial} =mgh=(5kg)(9.8m/ s^{2} )(0.8m)=39.2 joules
KE_{final}=39.2joules
solmaris [256]3 years ago
6 0

Answer:

39.2J

Explanation:

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Sort the chemical equations based on the chemical reactions they represent.
Svetradugi [14.3K]

Decomposition reactions are said to be those reactions in which a reactants breakdown into two or more products. The general reaction for decomposition reactions is as follow,

                                         ABC    →    A  +  B  +  C

Specific Examples are as,

                                Water    →     Hydrogen + Oxygen

                                2 H₂O    →           2 H₂     +      O₂

               Calcium carbonate    →     Calcium oxide + Carbon dioxide

                            CaCO₃              →              CaO         +        CO₂

While, Synthetic reactions are said to be those reactions in which two or more reactants combine to form two or more products. The general reaction for synthetic reactions is as follow,

                                         A  +  B  +  C    →    ABC

Specific Examples are as,

                                  Iron + Oxygen     →     Iron Oxide

                                    2 Fe  +  3 O₂      →        2 Fe₂O₃

                          Sodium + Chlorine     →     Sodium chloride

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                            Sulfur + Oxygen      →      Sulfur dioxide

                                  S    +    O₂            →             SO₂

                   Potassium + Chlorine      →      Potassium chloride

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4 0
2 years ago
Read 2 more answers
A snowball accelerates at
ANTONII [103]

Answer:

0. 1226495726kg

Explanation:

Force is the product of mass and acceleration.

Mathematically,

Force(F) = mass (m)×acceleration(a)

Substituting the values into the equation

2. 87=m×23. 4

2. 87=m (23. 4)

2. 87/23. 4=m (23. 4)/23. 4

2. 87/23. 4=m

0. 1226495726=m

8 0
2 years ago
g A ball thrown straight up into the air is found to be moving at 7.94 m/s after falling 2.72 m below its release point. Find th
kati45 [8]

The ball has height <em>y</em> and velocity <em>v</em> at time <em>t</em> according to

<em>y</em> = <em>v</em>₀ <em>t</em> - 1/2 <em>g</em> <em>t</em> ²

and

<em>v</em> = <em>v</em>₀ - <em>g t</em>

where <em>v</em>₀ is its initial speed and <em>g</em> = 9.80 m/s² is the magnitude of the acceleration due to gravity.

The ball is falling with a velocity of 7.94 m/s when it's 2.72 m below the release point, which at time <em>t </em>such that

-2.72 m = <em>v</em>₀ <em>t</em> - 1/2 <em>g</em> <em>t</em> ²

-7.94 m/s = <em>v</em>₀ - <em>g t</em>

Solve for <em>t</em> in the second equation:

<em>t </em>= (<em>v</em>₀ + 7.94 m/s)/<em>g</em>

Substitute this into the first equation and solve for <em>v</em>₀ :

-2.72 m = <em>v</em>₀ (<em>v</em>₀ + 7.94 m/s) /<em>g</em> - 1/2 <em>g</em> ((<em>v</em>₀ + 7.94 m/s)/<em>g</em>)²

-2.72 m = <em>v</em>₀²/<em>g</em> + (7.94 m/s) <em>v</em>₀/<em>g</em> - 1/2 (<em>v</em>₀ + 7.94 m/s)²/<em>g</em>

2 (-2.72 m) <em>g</em> = 2<em>v</em>₀² + 2 (7.94 m/s) <em>v</em>₀ - (<em>v</em>₀ + 7.94 m/s)²

2 (-2.72 m) (9.80 m/s²) = 2<em>v</em>₀² + (15.9 m/s) <em>v</em>₀ - (<em>v</em>₀² + (15.9 m/s) <em>v</em>₀ + 63.0 m²/s²)

-53.3 m²/s² = <em>v</em>₀² - 63.0 m²/s²

<em>v</em>₀² = 9.73 m²/s²

<em>v</em>₀ = 3.12 m/s

3 0
2 years ago
Which object will be considered to be in free fall
Pani-rosa [81]
It depends on what they are 
3 0
3 years ago
Read 2 more answers
If two objects of the same size move through the air at different speeds, which encounters the greater air resistance?a. The fas
blagie [28]

Answer:

Option A is correct.

(The faster object encounters more resistance)

Explanation:

Option A is correct. (The faster object encounters more resistance)

Air resistance depends on various factors:

  • Speed of the object
  • Cross-sectional area of the object
  • Shape of the object

Formula:

F=\frac{1}{2}C_d\rho A v^{2}

As the speed of the object increases the amount of Air resistance/drag increases on the object, as the above formula shows direct relation between Air resistance/drag and velocity i.e F ∝ v^2.

6 0
3 years ago
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