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krok68 [10]
3 years ago
11

2. How have human activities and natural processes influenced the gradual or sudden change in global temperature? (You need a mi

nimum of 5 complete sentences.)​
Physics
1 answer:
mote1985 [20]3 years ago
7 0

Answer:

Human activities and natural processes have influenced the change in the global temperature by the following processes

1) Green house gas such as carbon dioxide, methane, ozone, nitrous oxide and fluorinated gases produced by the combustion of fossil fuels the use of  industrial chemicals, the production of coal, and natural gas

2) Deforestation which reduces the natural process of conversion of carbon dioxide to oxygen, thereby, increasing the greenhouse gases in the atmosphere

3) The accumulation of the greenhouse gases in the atmosphere results in the trapping of heat in the atmosphere, causing the atmospheric temperature to rise

4) Changes in the amount of energy produced by the Sun can result in an increase or decrease in the atmospheric temperature

5) Volcanic activity that occurs at a sufficiently large scale can produce sulfur dioxide that blocks the rays of the Sun from reaching the Earth, resulting in a change of atmospheric temperature.

Explanation:

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If the wavelength of an electromagnetic wave is too long or too short,
Evgesh-ka [11]
it is no longer and electromagnetic wave.
3 0
3 years ago
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A 28.0 kg child plays on a swing having support ropes that are 2.30 m long. A friend pulls her back until the ropes are 45.0 ∘ f
Dimas [21]

Answer

A)184.9J

B)=3.63m/s

C) Zero

Explanation:

A)potential energy of the child at the initial position, measured relative the her potential energy at the bottom of the motion, is

U=Mgh

Where m=28kg

g= 9.8m/s

h= difference in height between the initial position and the bottom position

We are told that the rope is L = 2.30 m long and inclined at 45.0° from the vertical

h=L-Lcos(x)= L(1-cosx)=2.30(1-cos45)

=0.674m

Her Potential Energy will now

= 28× 9.8×0.674

=184.9J

B)we can see that at the bottom of the motion, all the initial potential energy of the child has been converted into kinetic energy:

E= 0.5mv^2

where

m = 28.0 kg is the mass of the child

v is the speed of the child at the bottom position

Solving the equation for v, we find

V=√2k/m

V=√(2×184.9/28

=3.63m/s

C)we can find work done by the tension in the rope is given using expresion below

W= Tdcosx

where W= work done

T is the tension

d = displacement of the child

x= angle between the directions of T and d

In this situation, we have that the tension in the rope, T, is always perpendicular to the displacement of the child, d. x= 90∘ and cos90∘=0 hence, the work done is zero.

6 0
3 years ago
6. How does the shape and size of the continents today help support the Theory of Continental Drift?
Ahat [919]
All the continents were connected in one large landmass.If you take a map and cut out all the Continent, you can see that they fit together almost perfectly, like a giant puzzle. This idea supports the fact that <span>all the continents were connected in one large landmass.
</span>hope it helped :)

5 0
3 years ago
Read 2 more answers
Calculate the The wavelength of the first Balmer series of hydrogen is 6562 following: a) The ionization potential, and b) The f
postnew [5]

Answer:

(a) 13.6 eV

(b) 10.2 V

Explanation:

a) Ionization potential energy is defined as the minimum energy required to excite a neutral atom to its ionized state i.e basically  the minimum energy required to excite an electron from n=1 to infinity.

Energy of a level, n, in Hydrogen atom is, E_{n}=-\frac{13.6}{n^{2} }

Now ionization potential can be calculated as

E_{\infty}- E_{0}

Substitute all the value of energy and n in above equation.

=-\frac{13.6}{\infty^{2}}-(-\frac{13.6}{1^{2}})\\=13.6eV

Therefore, the ionization potential is 13.6 eV.

b) This is the energy required to excite a atom from ground state to its excited state. When electrons jumps from ground state level(n=1) to 1st excited state(n=2) the corresponding energy is called 1st excitation potential energy and corresponding potential is called 1st excitation potential.

So, 1st excitation energy = E(n 2)- E(n = 1)

=-\frac{13.6}{2^{2}}-(-\frac{13.6}{1^{2}})\\=-3.4eV - (-13.6eV) \\=10.2eV

Now we can find that 1st excitation energy is 10.2 eV which gives,

eV'=10.2eV\\V'=10.2V

Therefore, the 1st excitation potential is 10.2V.

7 0
3 years ago
5) The temperature of water in a container was 60°C. Ten minutes later, the water
Sati [7]

Answer:

2.5 C/min

Explanation:

6 0
3 years ago
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